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3 years ago

Can someone help me with this math problem

Mathematics

1 answer:

melisa1 [442]3 years ago

6 0

Answer:

A. 5x+5

B. 10x + 13

C. 8x -2

D.3x -8

Step-by-step explanation:

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3 years ago

Average rate of change help!!

frez [133]

Given that the function is $f(x)=x^{3}-6 x^{2}+4 x+7$

We need to determine the average rate of change over the interval $0 \leq x \leq 5$

Value of f(x) when x = 0:

Substituting x = 0 in the function $f(x)=x^{3}-6 x^{2}+4 x+7$ , we have;

$f(0)=(0)^{3}-6 (0)^{2}+4 (0)+7$

$f(0)=0-0+0+7$

$f(0)=7$

Thus, the value of f(0) is 7.

Value of f(x) when x = 5:

Substituting x = 5 in the function $f(x)=x^{3}-6 x^{2}+4 x+7$ , we have;

$f(5)=(5)^{3}-6 (5)^{2}+4 (5)+7$

$f(5)=125-150+20+7$

$f(5)=2$

Thus, the value of f(5) is 2.

Average rate of change:

The average rate of change can be determined using the formula,

$Rate \ of \ change=\frac{f(b)-f(a)}{b-a}$

where $a=0$ and $b=5$

Thus, we have;

$Rate \ of \ change=\frac{f(5)-f(0)}{5-0}$

$Rate \ of \ change=\frac{2-7}{5-0}$

$Rate \ of \ change=\frac{-5}{5}$

$Rate \ of \ change=-1$

Thus, the average rate of change over the interval $0 \leq x \leq 5$ is -1.

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3 years ago

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eimsori [14]

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