First one:
Same denominator so ((9-7x)+(x-4))/(x+7)
Final answer:
(5-6x)/(x+7)

Second one:
Again same denominator so ((7x)-(11x))/(x-7)
Final answer:
(-4x)/(x-7)

Third one:
Same denominator again, ((9x)-(14x))/(x+9)
Final answer:
(-5x)/(x+9)

Fourth one:
Same denominator again, ((3x-4)-(x-9))/(x+6)
Final answer:
(2x+5)/(x+6)

Fifth one:
Different denominators here, so we have to make them them same. We do this by multiplying the first fraction by 3/3 to get (3x-9)/(2x), so ((3x-9)+(x-4))/(6x)
Final answer:
(4x-13)/(6x)

Sixth one:
This one is trickier, we have to multiply each by the others denominator, so ((11)*(x-2))/((x+9)*(x-2)) and ((3)*(x+9))/((x-2)*(x+9)) to get
(11x-22)/(x^2+7x-18) and (3x+27)/(x^2+7x-18)
Final answer:
(14x+5)/(x^2+7x-18)

Last one:
You can change the first fraction to 1/(x*(x-1)), then multiple the second fraction by (x-1)/(x-1) to get (x-1)/(x^2-x). Now add them.
Final answer:
(2-x)/(x^2-1)

Hope I helped :)

8 0

3 years ago

Check the apply π\6 is the reference angle for

belka [17]

$\pi = 180\\
 \frac{\pi}{6} = x\\ \pi x = \frac{180\pi}{6}\\ \pi x = 30 \pi \\ x = 30$