Answer:
15
Step-by-step explanation:
Answer:
Now, 3x 2+x+5⩾0
This is because b² −4ac=1−4×5×3
=−59 (roots are imaginary)
3x²+x+5=(x−3)² =x²+9−6x and x−3⩾0
2x²+7x−4=0
2x²+8x−x−4=0
2x(x+4)−1(x+4)=0
(2x−1)(x+4)=0
x= 1/2 and−4 but x≥3
∴ No solution.
lol hehehe
Answer:
45
Step-by-step explanation:
plug in 3 where the xs are
2(3)(6(3)-5(3))+(3)^2(5(3)-4(3)=45
2(3)=6
6(3)=18
-5(3)=15
(3)^2=9
5(3)=15
-4(3)=-12
g(5) means we substitute every x in the equation with a 5.
g(5) = (5)^2 - 4.
g(5) = 21.
Answer:
(2x + 1) (x + 2)
Step-by-step explanation:
2x² + 4x + 1x + 2
They are already arranged, so you just have to find the GCF. 2x² + 4x have the GCF of 2 and 1x + 2 have the GCF of 1.
2x (x + 2) + 1(x + 2)
Now you divide the whole thing by x + 2.
2x (x + 2) + 1(x + 2)/ x + 2
One of them cancels out leaving (2x + 1) and (x+2)
