An 8th-degree polynomial needs 9 terms that involve
x⁸, x⁷, ..., x¹, and x⁰.
x=10 implies that (x-10) is a factor of the polynomial according to the Remainder theorem.
Let the polynomial be of the form
f(x) = a₁x⁸ + a₂x⁷ + a₃x⁶ +a₄x⁵ + a₅x⁴ + a₆x³ + a₇x² + a₈x + a₉
The first few lines of the synthetic division are
10 | a₁ a₂ a₃ a₄ a₅ a₆ a₇ a₈ a₉ ( the first row has 9 coefficients)
-----------------------------------------
a₁
Answer:
The first row has 9 coefficients.
Answer:
I think its A, Because if you look at the problome A makes sense
To solve this, we need to know how to find the mean of a set of data and how to find the median of a set of data.
To find the mean, or often called the average, we should add all of the values up, and then divide it by the number of values.
588+838+691+818+846+725+605+732+750 = 6593
6593/9=732.556
The problem tells us we should round to the nearest point, so our mean credit score is 733.
To find the median, we need to order the data from lowest to highest and find out which credit score(s) are right in the middle. If there are 2 in the middle, we simply should add them and divide by 2 to get our median. An easy way to do this is after you order them, you simply cross off one on each side until there is only 1 (or 2) left.
588 605 691 725 732 750 818 838 846
605 691 725 732 750 818 838
691 725 732 750 818
725 732 750
732
Since we only have one number in the middle, we are done with the median! We know our median is 732.
Now we simply need to compare them and subtract the lower one from the higher one.
Mean:733
Median: 732
733>732
We know the mean is bigger, so we should subtract the median from the mean.
733=732=1
Using the logic above, we can see that the mean is 1 point higher than the median.
Alright,
you will need to solve for each variable to find if they got the equation correctly or not..
Let's start with h
isolate h
(1/2)h = A/(b1+b2)
Now we need to get rid of 1/2 we may do so by multiplying both sides by 2
h = 2(A/(b1+b2))
And that's not how they did it for h so Option D doesn't apply
Let's see C
Also doesn't apply since they multiplied 2 only by A rather than A/h
Let's see B
Also not correct they made the same mistake as with option C
Let's see A
again same mistake
when multiplying both sides by 2
the 2 should be as following

I believe you should contact your instructor and explain that non of the options is right.
Answer:
3x-2y
Step-by-step explanation:
log10^(3x-2y)
We know the base is base 10 since it is not written
log10 10^(3x-2y)
The log10 10 cancels
3x-2y