Answer:
1 < a < 13/5
Step-by-step explanation:
2 < 2a - 3(1 -a) < 10
2 < 2a - 3 + 3a < 10
2 < 5a - 3 < 10
2 + 3 < 5a - 3 + 3 < 10 + 3
5 < 5a < 13
5/5 < 5a/5 < 13/5
1 < a < 13/5
Step-by-step explanation:
or,(x-2)(x-4)+(3x-11)(x-3)/(x-3)(x-4)=(4x+13)/(x+1)
or,x^2-4x-2x+8+3x^2-9x-11x+33/x^2-4x-3x+12=(4x+13)/(x+1)
or,4x^2-4x-2x-9x-11x+8+33/x^2-7x+12=(4x+13)/(x+1)
or,4x^2-26x+41/x^2-7x+12=(4x+13)/(x+1)
or, (x+1)(4x^2-26x+41)=(4x+13)(x^2-7x+12)
or,4x^3-26x^2+41x+4x^2-26x+41=4x^3-28x^2+48x+13x^2-91x+156
or,-26x^2+4x^2+28x^2-13x^2+41x-26x-48x+91x=156-41
or,-7x^2+58x=115
or,-7x^2+58x-115=0
or,-(7x^2-58x+115)=0
or,7x^2-58x+115=0
or,7x^2-(35+23)x+115=0
or,7x^2-35x-23x+115=0
or,7x (x-5)-23 (x-5)=0
or, (x-5)(7x-23)=0
Either, Or,
(x-5)=0 (7x-23)=0
or,x=0+5 or,7x=23
:x=5 :x=23/7
Hence,x=5 or 23/7
Answer:
Option 4: r ≥ 6
Step-by-step explanation:
5(6+3r) + 7 ≥ 127
30 + 15r + 7 ≥ 127
37 + 15r ≥ 127
15r ≥ 90
r ≥ 6
Answer:
(1,3)
Step-by-step explanation:
Rotating clockwise means that you're rotating by a negative angle measure. The rule for rotating -90 degrees is (x,y)->(y,-x). X is (-3,1) so X' should be (1,3) since you negate -3 to get 3 and switch the x and y coordinates.
