Answer: i believe its 3
Step-by-step explanation:
The probability of drawing two blue marbles if the first marble is not replaced is 1/5
<h3>How to determine the probabilities?</h3>
<u>The probability of tossing a head and drawing a red marble</u>
The given parameters are:
White = 1
Blue =3
Red = 2
Total = 6
The probability of a head is
P(Head)= 1/2
The probability of drawing a red marble is
P(Red)= 2/6 = 1/3
The required probability is
P = P(Head) * P(Red)
This gives
P = 1/2 * 1/3
P =1/6
<u>The probability of drawing two blue marbles if the first marble is not replaced.</u>
Here, we have:
P(B1) = 3/6 = 1/2
P(B2) = 2/5
The required probability is
P = P(B1) * P(B2)
This gives
P = 1/2 * 2/5
P =1/5
Hence, the probability of drawing two blue marbles if the first marble is not replaced is 1/5
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Answer:
A or B i hope this helps! sorry
Step-by-step explanation:
First we need to find slope of given line −4x+3y=−2
So convert it into slope intercept form y=mx+b
−4x+3y=−2
3y=4x−2
y=4/3x−2/3
Comparing above equation with y=mx+b gives m=4/3
Hence slope of given line is 4/3.
<em>We need slope of perpendicular line which is always "negative reciprocal of given slope"</em>.
Negative of 4/3 is -4/3.
taking reciprocal gives -3/4
Hence slope of required perpendicular line is m=-3/4
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Now we need to find y-intercept of −7x−7y=6
y-intercept is always the y-value when x=0 so let's plug x=0 into −7x−7y=6
−7(0)−7y=6
0−7y=6
−7y=6
y=-6/7
y-intercept is also called "b" in y=mx+b
hence b=-6/7
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Now we know that slope of perpendicular line is m=-3/4 and y-intercept b=-6/7
so plug both into formula y=mx+b
We get Final answer is 
<h2>
Quadratic Function Equations</h2>
To find the equation of a parabola given the vertex and the zeroes, we can use the intercept form equation to help us:

- r and s = intercepts/zeros of the graph
<h2>Solving the Question</h2>
We're given:
- Zeros: -8, 4
- Maximum: (-2, 18)

⇒ Plug in the given information:

<h2>Answer</h2>
