There are 20 numbers in the set.
Given,
Set of numbers is 120
one number is increased by 300
and, mean increases to 135.
To find the how many numbers are in the set?
Now, According to the question:
Let the number of numbers be 'n'
Then, (sum of numbers)/n = 120
or, old sum = 120n
if one number is increased by 300, the new sum = (old sum + 300)
Then, (new sum)/ n= 135
or new sum = 135n = old sum + 300 = 120n + 300
The equation will be:
135n = 120n + 300
15n = 300
n = 20
Hence, There are 20 numbers in the set.
In the question:
The mean of a set of numbers is 120. if one number is increased by 300, the mean increases to 135.
Learn more about Equation at:
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2. Tuesday
3.1/7 and 0.14
4. neither likely or unlikely because most days occur 52 times through out the year.
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Answer:
The answers are;
m = 9, e = 9
Step-by-step explanation:
The question relates to right triangles with special properties;
The given parameters of the given right triangles are;
The measure of an interior angle of the triangle = 45°
The length of the given leg length of the triangle = (9·√2)/2
The length of the other leg length of the triangle = n
The length of the hypotenuse side = m
A right triangle with one of the measures of the interior angles equal to 45° is a special triangle that has both leg lengths of the triangle equal
Therefore;
The length of the other leg of the right triangle = n = The length of the given leg of the triangle = (9·√2)/2
∴ n = (9·√2)/2
n = (e·√f)/g
Therefore, by comparison, we have;
e = 9, f = 2, and g = 2
By Pythagoras's theorem, we have;
m = √(n² + ((9×√2)/2)² = √((9×√2)/2)² + ((9×√2)/2)²) = √(81/2 + 81/2) = √81 = 9
m = 9.
Answer The unit rate in calories per cracker is 7.
(I'll add explanation if needed)
I hope this helped! :)
Question is not well presented
The parabola y=x² is scaled vertically by a factor of 1/10.
What is the equation of the new parabola?
Answer:
The equation of the new parabola is 0.1x²
Step-by-step explanation:
Given
Parabola: y = x²
Scale = 1/10 = 0.1
The interpretation of this question is that; there's a need to scale the graph in ratio 1:10.
I.e; 1 unit on the parabola is being represented by 10 unit on the scale
So, x (on the new parabola) = 1/10 of old x.
So, the new equation of the parabola = 1/10x²
New equation = 0.1x²
Hence, the equation of the new parabola is calculated as 0.1x²
