Answer:
<h2>(-3,-6)</h2>
Step-by-step explanation:
hope it help you
plz follow me
0.31777777777. I am pretty sure. I used my calculator
Answer:
The answer is (x+3)^2+(y-4)^2=1
Step-by-step explanation:
The equation is (x-a)^2+(y-b)^2=r^2
In this equation, a and b are the coordinates of a center, and r is radius
Substituting given values, we obtain our answer.
The sum of the interior angles of all triangles is 180 degrees. This is a right triangle, thus we know two interior angle values (90 degrees and 29 degrees). To find the third, set the sum of all interior angle values equal to 180 and solve for g.
180 = 90 + 29 + g
Collect like terms.
180 = 119 + g
Subtract 119 from both sides.
61 = g
Find the sum using 61 for g to check work.
180 = 90 + 29 + g
180 = 90 + 29 + 61
180 = 180
Answer:
m∠g = 61°
Imx->0 (asin2x + b log(cosx))/x4 = 1/2 [0/0 form] ,applying L'Hospital rule ,we get
= > limx->0 (2a*sinx*cosx - (b /cosx)*sinx)/ 4x3 = 1/2 => limx->0 (a*sin2x - b*tanx)/ 4x3 = 1/2 [0/0 form],
applying L'Hospital rule again ,we get,
= > limx->0 (2a*cos2x - b*sec2x) / 12x2 = 1/2
For above limit to exist,Numerator must be zero so that we get [0/0 form] & we can further proceed.
Hence 2a - b =0 => 2a = b ------(A)
limx->0 (b*cos2x - b*sec2x) / 12x2 = 1/2 [0/0 form], applying L'Hospital rule again ,we get,
= > limx->0 b*(-2sin2x - 2secx*secx.tanx) / 24x = 1/2 => limx->0 2b*[-sin2x - (1+tan2x)tanx] / 24x = 1/2
[0/0 form], applying L'Hospital rule again ,we get,
limx->0 2b*[-2cos2x - (sec2x+3tan2x*sec2x)] / 24 = 1/2 = > 2b[-2 -1] / 24 = 1/2 => -6b/24 = 1/2 => b = -2
from (A), we have , 2a = b => 2a = -2 => a = -1
Hence a =-1 & b = -2
