The ears are involved in balance, but it's more than just them.
Your eyes are also important, as well as your body's sense of where it is in space.
Answer:
B
Explanation:
Amino acids fold to form the protein and give it its functionality. Different orders of amino acids fold differently and make a different shape. The shape of the protein defines its function. The function will vary wildly
Patterns incidence distribution and possible control of diseases as well as other factors pertaining to health
Answer:
(a) 1/2; (b) no
Explanation:
Glucose-6-phosphate dehydrogenase deficiency (G6PD) is an X-linked recessive disorder and the woman's father was diseased so it means that woman is a carrier of the allele but has normal phenotype. It means that she will have XXᵇ genotype.
In contrast to this, her husband is diseased so his genotype will be XᵇY.
The Punnett square diagram related to the cross is attached.
(a) Proportion of their sons expected to be G6PD is 1/2:
They both may give birth to 4 progeny with genotypes XXᵇ, XᵇXᵇ, XY and XᵇY. It means they both may have 2 sons out of which one with genotype XᵇY will be diseased while the one with genotype XY will be healthy. So the proportion of their sons having G6PD is 1/2 or 50%.
(b) If the husband were G6PD deficient, the answer will not change.
The reason behind this is that this disease is caused by an allele located in X chromosome. But father contributes only Y chromosome to his son not X chromosome. The X chromosome will affect the genotype of his daughter not son that is why answer will not change. It means they will still have 1/2 of their sons diseased.
Answer:
a. Let us consider that L is responsible for late and l is responsible for early. From the mentioned data, it can be concluded that allele L or late is dominant over early. By crossing plants 1 and 4 we get the expected ratio of 3: 1, which shows that it follows Mendel's law of dominant.
b. The genotype of all the four plants are:
1st plant = Ll
2nd plant = ll
3rd plant = LL
4th plant = Ll
c. If the plant 1 is self-fertilized then the expected progeny will be 3 (late): 1 (early).
In case if the 2nd plant is self-fertilized, the expected progeny will be only early.
In case if the 3rd plant is self-fertilized, the expected progeny will be only late.
In case if the 4th plant is self-fertilized, the expected progeny will be 3 (late): 1 (early).