The alue of 5 is the tenths place.
Answer:
80π
Step-by-step explanation:
Circle O with radius IO:
large radius = IO = 12 = R
Circle O with diameter JK
IJ = JK = KL = 2 × IO = 24
IJ = JK = KL = 24/3 = 8
small radius = 8/2 = 4 = r
The shaded area is a semicircle of radius 12 minus a semicircle of radius 4 plus two semicircles of radius 4.
That is the same as
1 semicircle of radius 12 plus 1 semicircle of radius 4
A = πR²/2 + πr²/2
A = π(12² + 4²)/2
A = 160π/2
A = 80π
3x^2 + 6x - 10 = 0
3(x^2 + 2x) - 10 = 0
3[ (x + 1)^2 - 1 ] - 10 = 0
3(x+1)^2 - 13 = 0
so the vertex is at (-1,-13)
the roots will be same distance from x = -1
that is a distance 1.08 --1 = 2.08
so other root is approximately -1 -2.08 = -3.08
the other intercept is at (-3.08,0)
The <em>correct answer</em> is:
The diagonals of the parallelogram are congruent.
Explanation:
In every parallelogram, opposite angles are congruent. This would not mean it is a rectangle.
Consecutive sides of a parallelogram are only congruent if the parallelogram is a rhombus or a square; this would not be a rectangle.
The diagonals of every parallelogram bisect each other. This would not mean it is a rectangle.
The diagonals of a rectangle bisect each other. If we know this is true about our parallelogram, this means our parallelogram is a rectangle.
5 wholes = 5
2 fifths = 2/5
5 - 2/5 = 4 3/5 (4 and 3 fifths)
Answer = 4 3/5
Check work:
4 3/5 + 2/5 = 5 (wholes)
