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Elanso [62]
3 years ago
10

Which variable in the following equation represents the slope of the line? y=mx+b ​

Mathematics
2 answers:
KiRa [710]3 years ago
7 0
The slope of an equation is determined by the m variable
aniked [119]3 years ago
4 0
M is the variable that represents the slope.

Hope this help!
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find the t values that form the boundaries of the critical region for a two-tailed test with a=.05 for n=6 n=12
AlexFokin [52]

Answer:

n=6

"=T.INV(1-0.025,5)", and we got the critical values given by: t_{critical}=\pm 2.5706  

n=12

"=T.INV(1-0.025,11)", and we got the critical values given by: t_{critical}=\pm 2.201  

Step-by-step explanation:

Previous concepts

The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".

The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.  

The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."

Solution to the problem

For n=6

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=6-1=5 degrees of freedom, a value that accumulates 0.05/2=0.025 of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,5)", and we got the critical values given by: t_{critical}=\pm 2.5706  

For n=12  

In order to find the critical value we need to take in count that we are conducting a two tailed test, so we are looking on the t distribution with df=n-1=12-1=11 degrees of freedom, a value that accumulates 0.05/2=0.025 of the area on each tail. We can use excel or a table to find it, for example the code in Excel is:  

"=T.INV(1-0.025,11)", and we got the critical values given by: t_{critical}=\pm 2.201  

3 0
4 years ago
the relationship between altitude and the boiling point is linear.AT an altitude of  8300ft 8300 ft , the liquid 
mojhsa [17]

Complete Question

The  relationship  between  altitude  and  the  boiling  point  is  linear. At  an  altitude  of   8300ft, the  liquid  boils  at   194.23 °  F

At  an  altitude  of   4200 ft ,  the  liquid  boils  at   202.02° F.

Write  an  equation  giving  the  boiling  point   b  of  the  liquid,  in  terms  of  altitude  a  in   feet . feet . What  is  the  boiling  point  of  the  liquid  at   2600ft

Answer:

The equation is  y  =  -0.001943x + 210.3569

At  2600ft  the temperature is  y  =  205.3051 \  °F

Step-by-step explanation:

From the question we are told that

    The temperature at 8300ft is 194.23 °  F

    The  temperature at 4200 ft is 202.02° F

Generally the slope for this relationship is mathematically represented as

      m  =  \frac{ 202.2 - 194.23}{ 4200 - 8300}

=>     m  = 0.001943  ^o  F / ft  

Generally the according to the point slope formula is

      y - y_1  =  m(x -x_1 )

=>   y - 194.23 =  -0.001943 (x - 8300 )

=>  y - 194.23 =  -0.001943x + 16.1269

=>  y  =  -0.001943x + 210.3569

Now we are given from the question that   x =  2600 ft

Then  

         y  =  -0.001943(2600) + 210.3569

=>      y  =  205.3051 \  °F

   

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8x + 2y= 10<br> Solve the equation for y ...?
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8x+2y=10
-8x -8x

2y=-8x+10
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2 2 2

y=-4x+5
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True im gonna say true

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