X^(2)+x-20 splitting the middle term
1 answer:
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Answer:
The difference in area between the trapezoid and the rectangle is 10 in²
Step-by-step explanation:
The dimensions of the trapezoid are given as follows;
Base 1, a = 12 in
Base 2, b = 10 in
Height, h = 10 in
Area, A of trapezoid;
The dimensions of the rectangle are given as follows;
Base = 12 in
Height = 10 in
Area, A of rectangle;
Base × Height = 12 × 10 = 120 in^2
Therefore, the difference in area between the two packages is found as follows;
Difference in area between trapezoid and rectangle = 120 - 110 = 10 in²
The difference in area between the trapezoid and the rectangle = 10 in².
Answer:
The equation for the circle is:
Step-by-step explanation:
Here, let us assume the two end points of the diameter are:
P (3,-1) and Q (-2,-1)
Now, as we knew diameter is the chord that passer through the center of the circle.
⇒ Mid point of DIAMETER = Center coordinates of the Circle
Let us assume O(x,y) is the center of the line segment PQ.
So, by MID POINT FORMULA:
⇒ The center coordinates of the circle = O(0.5,-1) ...... (1)
Now, RADIUS = Half of DIAMETER
Using DISTANCE FORMULA:
So, Radius = 5/2 = 2.5 units
Now, the equation of circle with radius r and center coordinate ( h,k) is given as:
Substitute r = 2.5 and (h,k) = (0.5,0) we get:
Hence the equation for the circle is: