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3 years ago

The diagram shows the intersections of several straight roads. The avenues run parallel to each other.

Mathematics

2 answers:

inysia [295]3 years ago

7 0

Answer:

Option 2. 226 ft.

Step-by-step explanation:

In this question avenues are parallel to each other. Distances of first avenue and second avenue from the point of intersection of Main and Oak are (140+180) ft and 140 ft respectively.

Distance of B from the point of intersection of Oak and Main is 113 ft.

Two similar triangles have been clearly formed by the first avenue and second parallel avenues.

Therefore by the property of similar triangles

(AB + 113)/113 = (280 + 140)/140 = 420/140 = 3

AB + 113 = 3 × 113

AB = 3 × 113 - 113 = 2×113 = 226 ft

Therefore Amana walks 226 ft along Oak.

trasher [3.6K]3 years ago

6 0

Answer:

226ft

Step-by-step explanation:

TOOK IT ON EDG

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A system of linear equations is graphed on this coordinate grid.

Serjik [45]

I think it is B (1,5) because that is where it intersects

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3 years ago

Find the distance between the points (-1,-7) and (8,-9). The answer must be a whole number or a fully simplified radical express

ruslelena [56]

Answer:

The answer is

<h2> $\sqrt{85} \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-7) and (8,-9)

The distance between them is

$d = \sqrt{( { - 1 - 8})^{2} + ({ - 7 + 9})^{2} } \\ = \sqrt{ ({ - 9})^{2} + {2}^{2} } \\ = \sqrt{81 + 4}$

We have the final answer as

$\sqrt{85} \: \: \: units$

Hope this helps you

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3 years ago

SAT scores have a mean of 1026 and a standard deviation of 209. ACT scores have a mean of 20.8 and a standard deviation of 4.8.

Y_Kistochka [10]

Answer:

The z-score for SAT exam of junior is much small than his ACT score. This means he performed well in his ACT exam and performed poor in his SAT exam.

Step-by-step explanation:

Mean SAT scores = 1026

Standard Deviation = 209

Mean ACT score = 20.8

Standard Deviation = 4.8

We are given SAT and ACT scores of a student and we have to compare them. We cannot compare them directly so we have to Normalize them i.e. convert them into such a form that we can compare the numbers in a meaningful manner. The best way out is to convert both the values into their equivalent z-scores and then do the comparison. Comparison of equivalent z-scores will tell us which score is higher and which is lower.

The formula to calculate the z-score is:

$z=\frac{x-\mu}{\sigma}$

Here, μ is the mean and σ is the standard deviation. x is the value we want to convert to z score.

z-score for junior scoring 860 in SAT exam will be:

$z=\frac{860-1026}{209}=-7.59$

z-score for junior scoring 16 in ACT exam will be:

$z=\frac{16-20.8}{4.8}=-1$

The z-score for SAT exam of junior is much small than his ACT score. This means he performed well in his ACT exam and performed poor in his SAT exam.

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Maksim231197 [3]

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eduard

Answer:

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