Hemophilia is a recessive X-linked condition and is inherited from parents. . The probability that Natalie and Daniel’s first child has hemophilia is<u> 1/4</u>, not 1/8. The statement is<u> false.</u> 
<h3>What is an X-linked gene?</h3>
When talking about sex-linked genes, we refer to all those genes located in one of the sex-chromosomes and not in the somatic ones. 
X-linked genes are the genes located specifically in the X sex chromosome. 
Traits coded by these genes are inherited. This is, X-linked genes are transmitted from parents to children through generations. 
According to this, X-linked genetic disorders will be inherited as well. 
- Men have a high probability of being affected since they only have one copy of the X chromosome. 
- In women, the effect of the mutation might be musk in heterozygous state if the mutation is recessive. 
Hemophilia is a recessive X-linked disorder, which means it is coded by the recessive allele.
- X+ ⇒ X chrosomosome with Dominant allele
- X- ⇒ X chrosomosome with Recessive allele
<u>Genotype              Phenotype</u>
X+X+                   Healthy woman
X+X-                    Healthy carrier woman
X-X-                     Hemophilic woman
X+Y                      Healthy man
X-Y                       Hemophilic man
Let us make a pedigree of these families, 
<u>Natalie's family</u>:
Mother         healthy carrier          X+X-
Father          healthy                      X+Y
Brother        hemophilic                X-Y  
Natalie         Healthy                     X+X- or X+X+   
Natalie has 1/2 chances of being carrier X+X- and 1/2 of being X+X+.
<u>Daniel's family</u>:
Mother         healthy carrier          X+X-
Father          hemophilic                X-Y  
Sister           hemophilic                X-X- 
Daniel          Healthy                      X+Y
He has 1/2 chances of being healthy X+Y and 1/2 of being affected X-Y.
According to the product probability rule, if events A and B are independent from each other, the probability of occurrence of both events together is 
P(A∩B) = P(A) x P(B)
In this case, 
- event A is Daniel being affected ⇒ 1/2
- event B is Natalie being carrier ⇒ 1/2
P(A∩B) = P(A) x P(B) = 1/2 x 1/2 = 1/4
The probability that Natalie and Daniel’s first child has hemophilia is 1/4, not 1/8. The statement is<u> false.</u> 
You can learn more about X-linked genes at
brainly.com/question/12420228
brainly.com/question/14704182
brainly.com/question/1387724
#SPJ1