Answer:
377 choices
Step-by-step explanation:
From the above question, we are told that
A restaurant offers 6 choices of appetizer, 8 choices of main meal and 5 choices of dessert. A customer can choose to eat just one course, or two different courses, or all three courses.
Let us represent each choice by :
A = Appetizer = 6
M = Main meal = 8
D = Dessert = 5
a) The combination of the 3 choices together
AMD=6 × 8 × 5=240
b) AM= Appetizer and Main meal
= 6 × 8 = 48
c) AD= Appetizer and Dessert
= 6 × 5 = 30
d) MD = Main meal × Dessert
= 8 × 5 = 40
e) A,M,D (each alone)=
Appetizer + Main meal + Dessert
= 6 + 8 + 5
= 19
Assuming all choices are available, how many different possible meals does the restaurant offer?
This is calculated as:
AMD + AM + AD + MD + A,M,D
240 + 48 + 30 + 40 + 19
= 377 choices
Answer:
26.6666... repeating
Step-by-step explanation:
20/3 = 6.6 repeating
.75/3 = .25
6.6 + 20 = 26.6 repeating
.25 + .75 = 1
Answer:
16.8
Step-by-step explanation:
equation: x - 3.9 = 12.9
add 3.9 to 12.9
answer is 16.8
I believe these are the answers.
A. congruent
B. isn't congruent
C. congruent
D. congruent
Hope this helps :D
