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S_A_V [24]
3 years ago
6

Plss can someone do this ive been trying for hourss

Mathematics
2 answers:
Talja [164]3 years ago
8 0

Answer:

(6+y) (6-y) / 6-y

Step-by-step explanation:

IRINA_888 [86]3 years ago
6 0

Answer:

Negative Infinity

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If using the method of completing the square to solve the quadratic equation, which number would have to be added to “complete t
Anna11 [10]
The answer is 80 because you add then subtract
6 0
3 years ago
Solve the equation for x by graphing -2x + 3 = -3(-x) - 2
adoni [48]

Answer:

  x = 1

Step-by-step explanation:

There are a couple of ways to solve this. One is to graph the left side of the equation, graph the right side of the equation, and look for the point where those graphs intersect. It is at x = 1. The first attached graph shows this solution.

__

Another method for solving such an equation is to subtract one side from the other and look for the value of x that makes the resulting expression zero.

  (-2x +3) -(-3(-x) -2) = 0

A graphing calculator doesn't need to have this simplified. If it is simplified, it becomes ...

  -5x +5 = 0

So, the graphed line is y = -5x+5. Its x-intercept is x=1, the solution of the original equation. The graph of this is shown in the second attachment.

6 0
3 years ago
Pls help me ????????????
ArbitrLikvidat [17]

Answer:

24 books

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
The article "Occurrence and Distribution of Ammonium in Iowa Groundwater" (K. Schilling, Water Environment Research, 2002:177–18
Papessa [141]

Answer: 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

Step-by-step explanation:

Since we have given that

Number of alluvial wells = 349

Number of quaternary wells = 143

Number of alluvial wells that had concentrations above 0.1 = 182

Number of quaternary wells that had concentrations above 0.1 = 112

Average of alluvial wells = 0.27

Standard deviation = 0.4

Average of quaternary wells = 1.62

Standard deviation =1.70

So, 95% confidence interval gives

alpha = 5% level of significance.

\dfrac{\alpha}{2}=2.5\%\\\\z_{\frac{\alpha}{2}}=1.96

So, 95% confidence interval becomes,

(1.62-0.27)\pm 1.96\sqrt{\dfrac{0.4^2}{349}+\dfrac{1.7^2}{143}}\\\\=1.35\pm 1.96\times 0.020\\\\=(1.35-0.040,1.35+0.040)\\\\=(1.31,1.39)

Hence, 95% confidence interval for the difference between the proportions would be (1.31, 1.39).

6 0
3 years ago
Pic included Please answer!!!
TiliK225 [7]
The answer is -4 + 7. Because its subtracting 4 to zero which makes it -4. And then its adding 7 so the answer is -4+7
4 0
4 years ago
Read 2 more answers
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