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nekit [7.7K]
3 years ago
13

2. The current cost of gourmet coffee is $14 per pound. At the corner market

Mathematics
1 answer:
Dominik [7]3 years ago
3 0

Answer:

<u>The cost two years ago = $11.57</u>

Step-by-step explanation:

The rest of the question is

what did a pound of gourmet coffee beans cost two years ago?

So, let the cost two years ago = x

The cost has increased 10% per year

so, the cost one year ago = x + 10% of x = x + 0.1 x = 1.1 x

So, the current cost = 1.1 x + 10% of 1.1 x = 1.1 x + 0.1 * 1.1 x = 1.21 x

But given the current cost = $14

∴ 1.21 x = 14

∴ x = 14/1.21 = 11.57

So, <u>the cost two years ago = $11.57</u>

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Type the correct answer in the box. Use numerals instead of words.
zhenek [66]

Answer:

1g - 50 = p(g)

Step-by-step explanation:

6 0
3 years ago
Last year prom tickets were 65 dollars and this year they are 50 dollars. What is the percentage difference
Solnce55 [7]
The difference between the percentages is 10%
4 0
4 years ago
Pls help quick!
oksano4ka [1.4K]

Answer:

v / √5

Step-by-step explanation:

Solution:-

- We have a satellite of mass ( m ) that orbits the earth of mass ( M ). The radius of orbit is ( r ) : center of earth - to - center of satellite radial distance.

- The satellite orbits the Earth with constant tangent velocity ( v ). The velocity  ( v ) is a function of massive body ( M ) about which the smaller body orbits and orbital radius ( r ).

- The formulation is given by:

                     v_o_r_b_i_t = \sqrt{\frac{G*M}{r} }  

Where,

          G: The universal gravitational constant

- We are to compare the orbital speeds by changing some of the parameters in the above relation.

- The effect on the orbital speed ( v_orbit ) by increasing the orbital radius to ( 5r ) can be evaluated using the given relation. Such that:

                     v_o_r_b_i_t = \sqrt{\frac{G*M}{5r} }\\\\v_o_r_b_i_t = \frac{1}{\sqrt{5} } \sqrt{\frac{G*M}{r} }\\

- Now take the ratio of initial orbital speed to the increased orbital radius ( 5r ):

                     v_o_r_b_i_t = \frac{1}{\sqrt{5} }*v \\

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=18x%20%2B%2020%20%2B%20x%20%3D%2010%28x%29%20-%203" id="TexFormula1" title="18x + 20 + x = 10(
Dima020 [189]

18x + 20 + x = 10x -3

Combine like terms

19x + 20 = 10x -3

Subtract 20 to both sides because whatever you do on one side you have to do it on the other side:

19x = 10x -23

Subtract 10x

9x = -23

Divide 9 to isolate x:

x = -23/9

Simplify to get a mixed number:

x = -2 5/9

4 0
4 years ago
Read 2 more answers
What is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D" id="TexFormula1" title="\frac{1}{2}" alt="\frac{1}{2}" align="a
RideAnS [48]

Hello!

<u><em>Answer: ⇒ 1/38</em></u>

Step-by-step explanation:

Convert element to fraction.

\frac{1}{2}\div \frac{19}{1}

Apply the fraction rule.

\frac{1}{2}*\frac{1}{19}

Then you can multiply by the fraction.

\frac{1*1}{2*19}

Multiply by the numbers.

1*1=1

\frac{1}{2*19}

=\frac{1}{38}

Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

5 0
3 years ago
Read 2 more answers
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