Let's simplify them top to bottom.
6(x + 2) < x - 3
6x + 12 < x - 3
5x + 12 < -3
5x < -15
x < -3
This one checks out.
3 + 4x <= 2(1 + 2x)
4x + 3 <= 4x + 2
This is a problem. In no world is 4x + 3 ever less than or equal to 4x + 2. This one has no solution.
Answer:
(h, k) is the point that represents the vertex of this absolute value function
Step-by-step explanation:
Recall that the vertex of an absolute value function occurs when the expression within the absolute value symbol becomes "zero", because it is at this point that the results in sign differ for x-values to the left and x-values to the right of this boundary point.
Therefore, in your case, the vertex occurs at x = h, and when x = h, then you can find the y-value of the vertex by looking at what f(h) renders:
f(h) = a | h - h | + k = 0 + k = k
Then the point of the vertex is: (h, k)
Answer:
A
Step-by-step explanation:
Hopefully this helps!
Answer:
25
Step-by-step explanation:
