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beks73 [17]
3 years ago
14

I need helppp!!! −50=10s

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
4 0
Hey the answer is -0.2. You have to divide 10 by both sides to isolate the variable
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From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c
sergiy2304 [10]

1:-

\\ \rm\Rrightarrow 4a+b+c+9a-c

\\ \rm\Rrightarrow 4a+9a+b+c-c

\\ \rm\Rrightarrow 13a+b

2:-

\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)

\\ \rm\Rrightarrow 18a-b-c-14a+2b+c

\\ \rm\Rrightarrow 18a-14a-b+2b-c+c

\\ \rm\Rrightarrow 4a+b

5 0
3 years ago
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Students are given 3 minutes to complete each multiple-choice question on a test and 8 minutes for each free-response question.
scoundrel [369]

Answer:

8(15 – m)

Step-by-step explanation:

Just Did The Test

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3 years ago
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The side of a square measures (2x − 5) units. Part A: What is the expression that represents the area of the square? Show your w
kolbaska11 [484]

A. The area of a square is given as:

<span>A = s^2 </span>

Where s is a measure of a side of a square. s = (2 x – 5) therefore,

<span>A = (2 x – 5)^2                   </span>

Expanding,

A = 4 x^2 – 20 x + 25

 

<span>B. The degree of a polynomial is the highest exponent of the variable x, in this case 2. Therefore the expression obtained in part A is of 2nd degree.</span>

Furthermore, polynomials are classified according to the number of terms in the expression. There are 3 terms in the expression therefore it is classified as a trinomial.

 

<span>C. The closure property demonstrates that during multiplication or division, the coefficients and power of the variables are affected while during multiplication or division, only the coefficients are affected while the power remain the same.</span>

5 0
3 years ago
Work out the difference between 38.3 and 1.72​
Bumek [7]

Answer:

36.58

Step-by-step explanation:

38.3-1.72=36.58

7 0
2 years ago
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Mr. Monasterio ran to the store for burritos at 4 miles per hour. On the way back, he increased his speed to 6 miles per hour. I
sveticcg [70]

Answer:

It took 1.2 hours to get to the store

Step-by-step explanation:

Let the time taken to reach the store be t₁

Let the time taken to come back be t₂

Let the speed to and from store = s₁ and s₂ respectively

let the distance to the store = d

To the store:

speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)

Back from the store:

s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)

We are told that total time (t₁ + t₂) = 2 hours

t₁ + t₂ = eqn (1) + eqn (2)

\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles

∴ length of trip to the store = t₁

from eqn (1)

t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours

7 0
3 years ago
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