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2 years ago

14

I need helppp!!! −50=10s

1 answer:

Nimfa-mama [501]2 years ago

4 0

Hey the answer is -0.2. You have to divide 10 by both sides to isolate the variable

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Which expression represents a number that is 4 times as great as the quotient of 25 and 5? A. ( 25 × 5 ) × 4 B. 4 ÷ ( 25 × 5 ) C

oksano4ka [1.4K]

Answer:

It would be D.

4 0

3 years ago

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The value of the expression 10 - 1/2^4 x 48<br> A = 2<br> B = 4<br> C = 5<br> D = 7

DaniilM [7]

Answer:

option d is correct answer

4 0

2 years ago

Which logarithmic equation is equivalent to the exponential equation below? E^a=35

oee [108]

Answer:

a = ln 35

Step-by-step explanation:

Given e^a = 35, take the natural log of both sides, obtaining:

ln e^a = ln 35. Recall that ln e^x = x, which means that ln e^a = a.

Then a = ln 35.

Next time, please share the answer choices!

7 0

2 years ago

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How to find the discriminant of

Evgen [1.6K]

the discriminant b^2 - 4ac when the equation is in the form of ax^2 +bx+c=0

13x^2-16x = x^2 -x

we need to get in it the standard form

subtract x^2 from each side

12x^2 -16x = -x

add x to each side

12x^2 -15x = 0

12x^2 -15x -0 =0

a=12 b=-15 c=0

b^2 -4ac

the discriminant = b^2

b^2 = (-15)2 = 225

6 0

3 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago