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LekaFEV [45]
3 years ago
9

Which statements can be used to prove that ABC and A’B’C are congruent?

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
7 0

Answer:

O A.

Step-by-step explanation:

<u>Option A</u> identifies two angles (sufficient for similarity) and one side, sufficient (with similarity) for congruence. The applicable congruence theorem is AAS.

<u>Option B</u> identifies two sides and the angle not between them. The two triangles will be congruent in that case only if the angle is opposite the longest side, which is <u>not true</u> in general.

<u>Option C</u> same deal as Option A.

<u>Option D</u> identifies three congruent angles, which will prove the triangles similar, but not necessarily congruent.

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Solve for a.
tamaranim1 [39]
The correct answer is:  [C]:  " a =  ± \sqrt{25 - b^2}  " .
<span>___________________________________________________________
Explanation:
_________________________________________________________
We are given:  
_________________________________________________________
    </span>→   "  25  =  a²  +  b²  "  ;   Solve for "a" ; 
_________________________________________________________

    →  To solve for "a" ;  we want to isolate "a" on one side of the equation.
_________________________________________________________
We can rewrite:  "  25  =  a²  +  b²  "  ;

as:  " a²  +  b²  = 25 " .

_________________________________________________________
Then, we can subtract " b² "  from each side of the equation; as follows:
_________________________________________________________

   →
 " a²  +  b²  −  b²  =  25 − b²  "  ;

to get:
_________________________________________________________
   →  " a²  =  25 − b²  "  ;
_________________________________________________________
  →  Now,  take the square root of EACH SIDE of the equation ; 
to isolate "a" on one side of the equation; & to solve for the value(s) of "a" ; 
_________________________________________________________

  →  √(a²)  = \sqrt{25 - b^2}  ;

to get:
_____________________________________________________
  →    a   =  | \sqrt{25 - b^2} |  ;

  →    a   =  ±  \sqrt{25 - b^2}  ; 
  
  →  which is:  Answer choice:  [C]:  " a =  ±  \sqrt{25 - b^2}  " .
______________________________________________________
8 0
3 years ago
Sami purchased 5 comic books priced as shown.
kati45 [8]

Answer:

$19.23

Step-by-step explanation:

First, add the prices of all 5 comics together. That should equal $17.63. The tax is 9% so that would be 1.5867 or $1.60. In total, Sami paid $19.23.

6 0
3 years ago
Read 2 more answers
. Andrew made an error in determining the polynomial equation of smallest degree whose roots are 3, 2+2i
KIM [24]

Answer:

Error of Andrew: Made incorrect factors from the roots

Step-by-step explanation:

Roots of the polynomial are: 3, 2 + 2i, 2 - 2i. According to the factor theorem, if a is a root of the polynomial P(x), then (x - a) is  a factor of P(x). According to this definition:

(x - 3) , (x - (2 + 2i)) , (x - (2 - 2i)) are factors of the required polynomial.

Simplifying the brackets, we get:

(x - 3), (x - 2 - 2i), (x - 2 + 2i) are factors of the required polynomial.

This is the step where Andrew made the error. The factors will always be of the form (x - a) , not (x + a). Andrew wrote the complex factors in form of (x + a)  which resulted in the wrong answer.

So, the polynomial would be:

(x - 3)(x - 2 - 2i)(x - 2+2i)=0\\\\ (x-3)(x^{2}-2x+2xi-2x+4-4i-2xi+4i-4i^{2})=0\\\\ (x-3)(x^{2}-4x+4+4)=0\\\\ (x-3)(x^{2}-4x+8)=0\\\\ x^{3}-4x^{2}+8x-3x^{2}+12x-24=0\\\\ x^{3}-7x^{2}+20x-24=0

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3 years ago
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Fofino [41]

Answer:

9

Step-by-step explanation:

18/2 is how to solve it.

Simp. to nine

6 0
3 years ago
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Ok so you do the table
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