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MrMuchimi
3 years ago
15

Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and

the same number of dimes. What is the largest number of groups she can have?
13
11
8
4​
Mathematics
1 answer:
Cerrena [4.2K]3 years ago
8 0

Answer:

8

Step-by-step explanation:

To find the largest number of groups she can have, find the largest number that can divide 104 and 88 evenly.

This number is 8, since 8 divides 104 to 13 and it divides 88 to 11.

This means each group will have 13 nickels and 11 dimes.

So, the answer is 8 groups.

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Find x, y and ab and how to check if the answer is right ​
iris [78.8K]

Answer:

  x = 2, y = -2, AB = 142

Step-by-step explanation:

The fact that X is the midpoint gives you two relations:

  AX = XB

  AX + XB = AB

Since you have two unknowns, this number of equations is sufficient to find their values. Substituting the given expressions in the above equations, you have ...

  • 8(3x+5) -3(y-7) -22x = 5x +y +23 -4(x-12)
  • 8(3x+5) -3(y-7) -22x + 5x +y +23 -4(x-12) = 2x -5y +128

Simplifying the first of these can make simplifying the second one easier.

  24x +40 -3y +21 -22x = 5x +y +23 -4x +48

  2x -3y +61 = x +y +71 . . . . . . we can use this simplification

  x -4y = 10 . . . . . . . . . . . . . . . . subtract x+y+61

Now, we can simplify the second equation to ...

  2x -3y +61 +x +y +71 = 2x -5y +128

  3x -2y +132 = 2x -5y +128 . . . . . simplify the left side

  x +3y = -4 . . . . . . . . . . . . . . . add -2x+5y-132

Then the two equations we need to solve are ...

  • x -4y = 10
  • x +3y = -4

Subtracting the second from the first, we get

  -7y = 14

  y = -2

Substituting into the first of these simplified equations, we get

  x -4(-2) = 10 . . . . substitute for y

  x +8 = 10 . . . . . . .evaluate

  x = 2 . . . . . . . . . .subtract 8

So, the solution is (x, y) = (2, -2).

Now, the values of AX and XB are ...

  AX = 2x -3y +61 = 2·2 -3(-2) +61 = 71

  XB = x+y+71 = 2 +(-2) +71 = 71 . . . . . . . . matches AX, a good sign

  AB = 2x -5y +128 = 2·2 -5(-2) +128 = 142 . . . . = AX+XB, another good sign

The desired values are x = 2, y = -2, AB = 142.

_____

You check the answer by filling the values into the expressions given in the problem statement and seeing if you get consistent results. Here, we used the simplified expressions, rather than the original expressions, so if we did the simplification wrong, we may have the wrong answer. It is always best to use the original equations. (A machine solver working with the original equations confirms our result, so "confidence is high.")

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(2x-6)(x+11)<br><br>a)x2-66x+16<br><br>b)x2+16x+11<br><br>c)2x2+16x-66<br><br>d)2x2+11x-66
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The answer to your math problem is C. The reason being is 2x times x is 2x^2 and 2x times 11 is 22x. So you first part of the problem looks like 2x^2+22. Then -6 times x is -6x and -6 times 11 is -66. So now the problem is 2x^2+22x-6x-66. So your answer after solving it is 2x^2+16x-66.
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