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Thepotemich [5.8K]
3 years ago
12

Find the value of x X

Mathematics
1 answer:
IgorLugansk [536]3 years ago
5 0

Answer:

20 or 18

Step-by-step explanation:

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What else would need to be congruent to show that JKL= MNO by AAS?
taurus [48]
Answer: Choice B) Angle L = Angle O

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If we know that Angle L is congruent to Angle O, then we can use the AAS (angle angle side) congruence property. We have one pair of angles marked by the square marker (angle J and angle M). So they are congruent angles. We have a pair of congruent sides JK = MN = 3. So we're just missing a pair of angles. 

Note: The answer is NOT angle K = angle N because this would mean ASA would be used instead of AAS. The order of the letters is important as it establishes how the sides and angles relate. With ASA, the side is between the angles. With AAS, the side is not between the angles. 

3 0
3 years ago
Read 2 more answers
What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
Tamiku [17]

Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

I = \frac{P}{4\pi d^{2}}

<em>where P: is the power ans d: is the distance. </em>

Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

\frac{I_{1}}{I_{2}} = \frac{P/4\pi d_{1}^{2}}{P/4\pi d_{2}^{2}}

<em>where I₁ = P/4πd₁², d₁=19 km, I₁ = P/4πd₂² and d₂=46 km     </em>

\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

3 0
3 years ago
Write 10 5/12 as an equivalent improper fraction.
velikii [3]
10\frac{5}{12} =\frac{(10\times12)+5}{12}=\frac{120+5}{12} =\boxed{\bf{\frac{125}{12}}}

Your final answer is A. 125/12
4 0
3 years ago
Read 2 more answers
A circle with area 16pi has a sector with a central angle of 8/5pi radians. What is the area of the sector?
lianna [129]

Answer:

The area of the sector is 12.8\pi\ units^2

Step-by-step explanation:

we know that

The area of a complete circle (16π units^2) subtends a central angle of 2π radians

so

using proportion

Find out the area of a sector , if the central angle is equal to 8π/5 radians

\frac{16\pi}{2\pi}=\frac{x}{(8\pi/5)}\\\\x=8(8\pi/5)\\\\x= 12.8\pi\ units^2

4 0
3 years ago
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Three planets are in line and are orbiting round a sun, one take 1 week to orbit the sun another takes 9 weeks and the other tak
patriot [66]

Answer:

27 weeks.

Step-by-step explanation:

You need to calculate the minimun common multiple between the three times.

1 week = 1^1 week

9 weeks = 3^2 weeks

27 weeks = 3^3 weeks

You take the 1 and the 3 with the biggest exponent and multiply. In this case is 1^1*3^3 = 27. So, in 27 weeks the pkanets will all be in alignment.

7 0
3 years ago
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