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crimeas [40]
3 years ago
13

ATTENTION

Mathematics
2 answers:
lakkis [162]3 years ago
5 0
<h2>▪Answer: Option D!</h2>

<h3>Explanation:</h3>

Given:

  • y = x +7
  • y =  {x}^{2}  + 2x + 7
<h2>Solution :</h2>

<em>Substitute</em><em> </em><em>y</em><em>=</em><em>x</em><em> </em><em>+</em><em> </em><em>7</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>second</em><em> </em><em>equation</em><em>!</em>

<em>y =  {x}^{2}  + 2x + 7</em>

<em>\implies \: x + 7 =  {x}^{2}  + 2x + 7</em>

<em>\implies \:  {x}^{2}  + 2x + 7 - x - 7 = 0</em>

<em>\implies \:  {x}^{2}  + x = 0</em>

<em>\implies \: x(x + 1) = 0</em>

<em>\implies \: x = 0 \: or \: x =  - 1</em>

<em>Now</em><em> </em><em>put</em><em> </em><em>x</em><em> </em><em>=</em><em> </em><em>0</em><em> </em><em>in</em><em> </em><em>equation</em><em> </em><em>1</em><em>,</em>

y = x +7

=> y = 0+7

<em>=></em><em> y = 7</em>

Now put x=-1 in equation 1,

y = x+7

=> y = -1+7

<em>=> y = 6</em>

<h3>The solutions are :</h3>

  • <em>(</em><em>0</em><em>,</em><em>7</em><em>)</em><em> </em><em>and</em>
  • <em>(</em><em>-1</em><em>,</em><em> </em><em>6</em><em>)</em>

<h2><em>Option</em><em> </em><em>D</em><em>!</em></h2>
Vlad1618 [11]3 years ago
4 0

Answer:

D

Step-by-step explanation:

plugin 0 for all x's to find the y-intercept

A doesn't work because if you plug in 1 for x in the first equation you get 10 and for the second equation you get 8. 10 and 8 are not equal

when you plug in -1 for x in both equation you get -6

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