Question

ATTENTION

Answer 1

▪Answer: Option D!

Explanation:

Given:

• y = x +7
• $y = {x}^{2} + 2x + 7$

Solution :

Substitute y=x + 7 in the second equation!

$y = {x}^{2} + 2x + 7$

$\implies \: x + 7 = {x}^{2} + 2x + 7$

$\implies \: {x}^{2} + 2x + 7 - x - 7 = 0$

$\implies \: {x}^{2} + x = 0$

$\implies \: x(x + 1) = 0$

$\implies \: x = 0 \: or \: x = - 1$

Now put x = 0 in equation 1,

y = x +7

=> y = 0+7

=> y = 7

Now put x=-1 in equation 1,

y = x+7

=> y = -1+7

=> y = 6

The solutions are :

• (0,7) and
• (-1, 6)

Option D!

Answer 2

Answer:

D

Step-by-step explanation:

plugin 0 for all x's to find the y-intercept

A doesn't work because if you plug in 1 for x in the first equation you get 10 and for the second equation you get 8. 10 and 8 are not equal

when you plug in -1 for x in both equation you get -6