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Westkost [7]
3 years ago
9

Three times a certain number is added to 5 and the result is 20? What's the number?

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
6 0

Answer:

The number is 5

Step-by-step explanation:

First of all we have to convert the given scenario in mathematical or algebraic expression.

Let x be the number

Then according to given statement, the equation will be:

"Three times a certain number"

3x

"is added to 5"

3x+5

"the result is 20"

3x+5 = 20

Using Subtraction property of Equality

3x+5-5 = 20-5\\3x = 15

Using division property of equality

\frac{3x}{3} = \frac{15}{3}\\x = 5

Hence,

The number is 5

Tems11 [23]3 years ago
5 0

Answer:

5

Step-by-step explanation:

5*3=15

+5=20

three times a certain number (5) is added to 5 and the result is 20

3*5+5=20

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Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

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Answer:

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Step-by-step explanation:

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