Answer:
Step-by-step explanation:
Ix-4I+3=3
subtracting 3 from both sides (*as per general practice in equations unknown are on one side and constants on the other side or simply taking 3 to other side of the equation)
Ix-4I+3-3=3-3
Ix-4I=0
x-4=0
x-4+4=0=4
x=4
checking:
I4-4I+3=3
I0I+3=3
3=3
9514 1404 393
Answer:
- DE ≈ 9.49, EF ≈ 8.06, FD ≈ 14.87
- obtuse scalene triangle
Step-by-step explanation:
For finding side lengths, it is convenient to work with the differences of the coordinates.
DE = E(-1, -3) -D(8, -6) = (-9, 3)
EF = F(-2, 5) -E(-1, -3) = (-1, 8)
FD = D(8, -6) -F(-2, 5) = (10, -11)
Then the lengths are ...
DE = √((-9)² +3²) = √90 = 3√10 ≈ 9.49
EF = √((-1)² +8²) = √65 ≈ 8.06
FD = √(10² +(-11)²) = √221 ≈ 14.87
The lengths are all different and the largest angle is obviously more than 90°, so the triangle is an obtuse scalene triangle.
Divide 13 into 29:
2.230769230769....
13 ) 29.0000000
26
—-
3 0 this remainder repeats 6 steps further down
2 6
——
40
39
——
100
91
——
90
78
—
120
11 7
—-
30 which will lead to a recurring decimal because we had remainder 3 at the beginning
We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:
<h3>
Presenting the equation:</h3>
Basically, we want to solve:
![\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-1%262%5C%5Ca%261%5Cend%7Barray%7D%5Cright%5D%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7Db%26c%5C%5C1%26d%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D1%260%5C%5C0%261%5Cend%7Barray%7D%5Cright%5D)
The matrix product will be:
![\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D-b%20%2B%202%26-c%20%2B%202d%5C%5Ca%2Ab%20%2B%201%26a%2Ac%20%2B%20d%5Cend%7Barray%7D%5Cright%5D)
Then we must have:
-b + 2 = 1
This means that:
b = 2 - 1 = 1
We also need to have:
a*b + 1 = 0
we know the value of b, so we just have:
a*1 + b = 0
Now the two remaining equations are:
-c + 2d = 0
a*c + d = 1
Replacing the value of a we get:
-c + 2d = 0
-c + d = 1
Isolating c in the first equation we get:
c = 2d
Replacing that in the other equation we get:
-(2d) + d = 1
-d = 1
Then:
c = 2d = 2*(-1) = -2
So the values are:
If you want to learn more about systems of equations, you can read:
brainly.com/question/13729904
Answer:
b = a² + 2a
Step-by-step explanation:
a + 1 = √(b + 1)
(a + 1)² = b + 1 (Square both sides)
a² + 2a + 1 = b + 1 (Expand left side)
a² + 2a = b (Subtract 1)