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3 years ago

Write 300 + 90 + 4 + 0.5 + 0.07 in standard form

Mathematics

2 answers:

satela [25.4K]3 years ago

7 0

$300+90+4+0.5+0.07 \to \boxed{394.57}$

asambeis [7]3 years ago

5 0

394.57 your welcome I am a bdjshdyjrhruy

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What is the greatest commen factor of 65 and 39

Ksivusya [100]

Going through the factors of 39:
1, 3, 13, 39

Now, the only numbers that goes into 65 without a remainder are 13 and 1.

Since 13 is greater, it is the GCF.

Hope this helped!

4 0

4 years ago

Read 2 more answers

If right i will mark brainlist 20 extra points

Fynjy0 [20]

As you may have noticed the formula for gradient is

(Change in yy)/(change in xx)

Therefore

(−5−15)/(−8−−2)(−5−15)/(−8−−2)

=−20/−6=−20/−6

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4 0

3 years ago

What is the sequence technique of this number sequence 3 20 78 334 1696 ?

polet [3.4K]

3×2+14=20
20×3+18=78
78×4+22=334
334×5+26=1696
1696×6+30=10206
Hence, the question mark should be replaced by 10206

3 0

4 years ago

Multiply the polynomials. (3x+4x+ 4)(2x - 4)

alexandr402 [8]

Answer:

Step-by-step explanation:

( 3x² + 4x + 4)(2x - 4)

(6x³ - 12x² + 8x² - 16x + 8x -16)

(6x³ - 4x² - 8x - 16)

Hope this helps!

3 0

3 years ago

Solve this pleasee!!!!!!!!!!!

Sholpan [36]

Answer:

1) Solution (2,-3)

2) Solution (-1, $-\frac{3}{2}$ )

3) Solution ( $\mathbf{-\frac{1}{2},-\frac{5}{2}}$ )

Step-by-step explanation:

We need to solve equations using elimination

1) $2x+2y=-2\\3x-2y=12$

Let:

$2x+2y=-2--eq(1)\\3x-2y=12--eq(2)$

Adding both equations:

$2x+2y=-2\\3x-2y=12\\--------\\5x=10\\x=\frac{10}{5}\\x=2$

We get value of x = 2

Now, put value of x into equation 1 to find value of y

$2x+2y=-2\\Put\:x=2\\2(2)+2y=-2\\4+2y=-2\\2y=-2-4\\2y=-6\\y=-6/2\\y=-3$

So, we get y = -3

Solution (2,-3)

2) $4x-2y=-1\\-4x+4y=-2$

Let:

$4x-2y=-1--eq(1)\\-4x+4y=-2--eq(2)$

Adding both equations

$4x-2y=-1\\-4x+4y=-2\\------\\2y=-3\\y=\frac{-3}{2}$

We get: y= -3/2

Now find value of x by putting value of y in eq(1)

$4x-2y=-1\\Put\:y=\frac{-3}{2}\\4x-2( \frac{-3}{2})=-1\\4x+3=-1\\4x=-1-3\\4x=-4\\x=\frac{-4}{4}\\x=-1$

We get x = -1

Solution (-1, $-\frac{3}{2}$ )

3) $x-y=2\\x+y=-3$

let:

$x-y=2--eq(1)\\x+y=-3--eq(2)$

Add both equations:

$x-y=2\\x+y=-3\\-----\\2x=-1\\x=-\frac{1}{2}$

We get x = -1/2

Now, put value of x in equation 2

$x+y=-3\\-\frac{1}{2}+y=-3\\y=-3+ \frac{1}{2}\\y=\frac{-6+1}{2}\\y=\frac{-5}{2}$

We get y = -5/2

Solution ( $\mathbf{-\frac{1}{2},-\frac{5}{2}}$ )

7 0

3 years ago