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3 years ago

Write 300 + 90 + 4 + 0.5 + 0.07 in standard form

Mathematics

2 answers:

satela [25.4K]3 years ago

7 0

$300+90+4+0.5+0.07 \to \boxed{394.57}$

asambeis [7]3 years ago

5 0

394.57 your welcome I am a bdjshdyjrhruy

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What is these answers

lianna [129]

1. 15
2. 9/14
3. 5/8
4. 2
5. 8.4*10 exponent -3
6. 90
7. 0.0025
8. -60
9. 15

For 9 I’m not that sure but I’m guessing it’s an absolute value question???

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2 years ago

Read 2 more answers

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julsineya [31]

Answer:

Part 1) $sin(\theta)=-\frac{\sqrt{65}}{9}$

Part 2) $tan(\theta)=\frac{\sqrt{65}}{4}$

Step-by-step explanation:

we have that

The cosine of angle theta is negative and the tangent of angle theta is positive

That means that the sine of angle theta is negative

step 1

Find $sin(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$cos(\theta)=-\frac{4}{9}$

substitute

$sin^{2}(\theta) +(-\frac{4}{9})^{2}=1$

$sin^{2}(\theta) +\frac{16}{81}=1$

$sin^{2}(\theta)=1-\frac{16}{81}$

$sin^{2}(\theta)=\frac{65}{81}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{65}}{9}$

Remember that

In this problem the sine of angle theta is negative

$sin(\theta)=-\frac{\sqrt{65}}{9}$

step 2

Find $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=-\frac{\sqrt{65}}{9}$

$cos(\theta)=-\frac{4}{9}$

substitute the given values

$tan(\theta)=-\frac{\sqrt{65}}{9}:-\frac{4}{9}=\frac{\sqrt{65}}{4}$

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