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3 years ago

PLEASE HELP!! WILL MARK BRAINLIEST!!

Computers and Technology

1 answer:

Kobotan [32]3 years ago

7 0

Answer:

Wow, that’s pretty good question.

I would probably get a vpn because it gives free secure WiFi. And it’s most reliable.

Hope I helped!

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Gimme Shelter Roofers maintains a file of past customers, including a customer number, name, address, date of job, and price of

gulaghasi [49]

Answer:

Hence the complete implementation of python code that reads two files and merges them together.

def merge_file(past_file_path,proposed_file_path, merged_file_path):

past_file_contents=load_file(past_file_path)

proposed_file_contents=load_file(proposed_file_path)

proposed_customer_name = []

for row in proposed_file_contents:

proposed_customer_name.append(row[1])

with open(merged_file_path,'w') as outputf:

outputf.write("Customer Number, Customer Name, Address\r\n")

for row in proposed_file_contents:

line = str(row[0]) +", " + str(row[1]) + ", " + str(row[2]) +"\r\n"

outputf.write(line)

for row in past_file_contents:

if row[1] in proposed_customer_name:

continue

else:

line = str(row[0]) + ", " + str(row[1]) + ", " + str(row[2]) + "\r\n"

outputf.write(line)

print("Files merged successfully!")

# reads the file and returns the content as 2D lists

def load_file(path):

file_contents = []

with open(path, 'r') as pastf:

for line in pastf:

cells = line.split(",")

row = []

for cell in cells:

if(cell.lower().strip()=="customer number"):

break

else:

row.append(cell.strip())

if len(row)>0:

file_contents.append(row)

return file_contents

past_file_path="F:\\Past Customer.txt"

proposed_file_path="F:\\Proposed Customer.txt"

merged_file_path="F:\\Merged File.txt"

merge_file(past_file_path,proposed_file_path,merged_file_path)

8 0

3 years ago

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uysha [10]

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3 years ago

Which social networking site became a gaming platform after 2009?

Art [367]

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3 years ago

Read 2 more answers

Write the following program in C++ to print:

Alenkinab [10]

1.
#include <iostream>#include <string>
using namespace std;
int main(){ string chars; // This is where we will put our @ signs and print them for(int x=0;x < 5; x++){
chars = chars + '@'; // This will concatenate an @ sign at the end of the variable cout << chars << "\n"; }}

2.
#include <iostream>#include <string>
using namespace std;
int main(){ string name; // Our variable to store the name cout << "What is your name? \n"; // Asks the user for their name cin >> name; cout << "\nWell, hello " << name << "!";}

3.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; // Asks for a number cin >> number; cout << "You entered " << number << "%!";}

4.
#include <iostream>#include <string>
using namespace std;
int main(){ int number; // Our variable cout << "Enter a number\n"; cin >> number;
int check = number % 2; // The modulo operator (the percent sign) gets the remainder of the quotient if (check == 0) { cout << number << " is even!"; // If the remainder is 0 then it prints out "x is even" } else { cout << number << " is odd!"; // If the remainder is not 0 then it prints out "x is odd" }}

5.
#include <iostream>#include <string>
using namespace std;
int main(){ float r; // Our variable cout << "Enter a radius\n"; cin >> r; if (r < 0){ cout << "Lol. No."; // If the radius is less than zero print out that message } float circumference=2*3.14*r; float area=r*r*3.14; cout << "\n\n Circumference of circle: " << circumference; cout << "\n Area of circle: " << area;}

4 0

3 years ago

In c++

Elodia [21]

Answer:

class studentType: public personType

{

public:

virtual void print() = 0;

virtual void calculateGPA() = 0;

void setID(long id) {

studentId = id;

}

void setCourses(const string c[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

courses[i] = c[i];

}

void setGrades(const char cG[], int noOfC) {

noOfCourses = noOfC;

for (int i=0; i<noOfCourses; i++) {

coursesGrade[i] = cG[i];

}

long getID() {

return studentId;

}

string* getCourses() {

return courses;

}

char* getGrades() {

return coursesGrade;

}

studentType(string fName = "", string lastName = "",

long id = 0, string c[] = NULL, char cG[] = NULL, int noOfC = 0);

private:

long studentId;

string courses[6];

char coursesGrade[6];

int noOfCourses;

};

Explanation:

Code rewritten

5 0

3 years ago