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exis [7]
2 years ago
13

Which equation is 3 a solution for​

Mathematics
2 answers:
liubo4ka [24]2 years ago
5 0

Answer:

3x-9=0

Step-by-step explanation:

I think so plus u can ask googl

TiliK225 [7]2 years ago
5 0

Answer:

x-3        -    log3  27 -         log2  (x+1)-log2 (x-4) =3

Step-by-step explanation:

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Which expression can be simplified as
DedPeter [7]

Answer:

4th is correct answer. 1, 2, 3 not correct you can check the exponents properties

3 0
3 years ago
I need a little bit of more help understanding how to do this
taurus [48]
Add 3 to both sides, then add 2m
Then divide 4 on both sides.
3 0
3 years ago
A rectangle has a height of a² + 3 and a width of a² + 2a + 5.
valentina_108 [34]

Answer:

Area =  a^4+2a^3+8a^2+6a+15

Step-by-step explanation:

The area of a rectangle is given by:

Area = Height * Width

The expressions for height and width are given. We just need to multiply and add like terms (if applicable) to find the expression for the area of the rectangle.

Remember to use distributive property:

(a+b)(x+y) = ax + ay + bx + by

Thus, we have:

(a^2+3)(a^2+2a+5)\\=(a^2)(a^2)+(a^2)(2a)+(a^2)(5)+3a^2+6a+15\\=a^4+2a^3+5a^2+3a^2+6a+15\\=a^4+2a^3+8a^2+6a+15

THis is the expression for area.

5 0
3 years ago
It is estimated that 0.54 percent of the callers to the Customer Service department of Dell Inc. will receive a busy signal. Wha
stira [4]

Using the binomial distribution, it is found that there is a 0.8295 = 82.95% probability that at least 5 received a busy signal.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 0.54% of the calls receive a busy signal, hence  p = 0.0054.
  • A sample of 1300 callers is taken, hence n = 1300.

The probability that at least 5 received a busy signal is given by:

P(X \geq 5) = 1 - P(X < 5)

In which:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4).

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{1300,0}.(0.0054)^{0}.(0.9946)^{1300} = 0.0009

P(X = 1) = C_{1300,1}.(0.0054)^{1}.(0.9946)^{1299} = 0.0062

P(X = 2) = C_{1300,2}.(0.0054)^{2}.(0.9946)^{1298} = 0.0218

P(X = 3) = C_{1300,3}.(0.0054)^{3}.(0.9946)^{1297} = 0.0513

P(X = 4) = C_{1300,4}.(0.0054)^{4}.(0.9946)^{1296} = 0.0903

Then:

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0009 + 0.0062 + 0.0218 + 0.0513 + 0.0903 = 0.1705.

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.1705 = 0.8295

0.8295 = 82.95% probability that at least 5 received a busy signal.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

6 0
1 year ago
Sally has £520
PIT_PIT [208]

Answer:

£132

Step-by-step explanation:

15% of  520 is 78

15% of 360 is 54

78 + 54 = 132

6 0
2 years ago
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