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mina [271]
2 years ago
14

What's

2} - {y}^{2} " alt=" {x}^{2} - {y}^{2} " align="absmiddle" class="latex-formula">

( where, x = 12 and y = 11 )​
Mathematics
1 answer:
klio [65]2 years ago
4 0

Answer:

here's your solution

=> we need to solve this ( x^2 -y^2)

=> it is given that x = 12 y= 11

=> now putting the value of these in question

=>. 12^2 - 11^2

=> 144 - 121

=. 23

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Answer:

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

Step-by-step explanation:

x=2-3\cos(t)

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Let's solve for \cos(t) in the first equation and then solve for \sin(t) in the second equation.

I will then use the following identity to get right of the parameter, t:

\cos^2(t)+\sin^2(t)=1 (Pythagorean Identity).

Let's begin with x=2-3\cos(t).

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Subtract 1 on both sides:

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Divide both sides by 4:

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Now let's plug it into our Pythagorean Identity:

\cos^2(t)+\sin^2(t)=1

\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1

\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1

\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1

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