The question is asking to calculate the zeros of the function f(x)=(5x^2+2x)/x, base on that and in my further calculation, the possible answer would be x=5. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications
Slope-intercept form:
y = mx + b
"m" is the slope, "b" is the y-intercept (the y value when x = 0)
You need to find "m" and "b".
In the table, when x = 0, y is 0, so the y-intercept is 0
y = mx + 0 or y = mx
To find "m", you can use the slope formula and plug in 2 points:
(0,0) and (1, 3)


m = 3
Slope: 3
y-intercept: 0
Equation: y = 3x
For lines to be perpendicular to each other their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1
Since y=2x-1 has a slope of 2, our perpendicular line must have a slope of:
2m=-1, m=-1/2, so our perpendicular line will be of the form:
y=-x/2+b, using the point (-2,-2) we can solve for the y-intercept, or "b".
-2=--2/2+b
-2=1+b
b=-3, then our perpendicular line is:
y=-x/2-3 or more neatly
y=-0.5x-3
Answer:
I don't know
Step-by-step explanation:
so
a= 5.237
b= 5x +2xy = 7xysq
c= 32.54 = x to the second power
d= 6x7
Answer:

Step-by-step explanation:
So we have the rational expression:

In rational expressions, the restrictions of the expression would be the zeros of the denominator Therefore, set the denominator equal to zero and solve for its zeros:

Zero Product Property:

Solve for a and b:

Therefore, the restrictions on the variables are that a and b cannot equal zero.