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solmaris [256]
3 years ago
12

the sum of the digits of a two number is 14 .if 36 is substracted from the number,the places of the digits are reversed.find the

number​
Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0
The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x

Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y

10y+ x-36=10x+y
Substitute y with 14-x
So we would get

10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5

Y=14-x
=14-5
=9


So the two digit number is
10y+x
=90+5
=95
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Which recursive sequence would produce the sequence 8,-35,137,…?
vagabundo [1.1K]

The recursive sequence that would produce the sequence 8,-35,137,… is T(n + 1) = -3 - 4T(n) where T(1) = 8

<h3>How to determine the recursive sequence that would produce the sequence?</h3>

The sequence is given as:

8,-35,137,…

From the above sequence, we can see that:

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So, we have:

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Rewrite as:

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brainly.com/question/1275192

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you are right, it's a)❤

Step-by-step explanation:

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.

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hope it helps❤

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