Question

the sum of the digits of a two number is 14 .if 36 is substracted from the number,the places of the digits are reversed.find the number​

Answer 1

The number in the ones place= X
The number in the tenths place= y
y+x=14.
y=14-x

Original placement of numbers=10y+x
New placement of numbers(after subtraction of 36)= 10x+y

10y+ x-36=10x+y
Substitute y with 14-x
So we would get

10(14-x)+ x-36=10x+(14-x)
=140-10x+x-36=10x+14-x
After transposing we get
140-14-36=10x-x+10x-x
=90=18x
X=90/18
x=5

Y=14-x
=14-5
=9


So the two digit number is
10y+x
=90+5
=95