Answer:
A sample of 997 is needed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the z-score that has a p-value of
.
The margin of error is of:

A previous study indicates that the proportion of left-handed golfers is 8%.
This means that 
98% confidence level
So
, z is the value of Z that has a p-value of
, so
.
How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?
This is n for which M = 0.02. So






Rounding up:
A sample of 997 is needed.
Answer:
4 gigabytes
Step-by-step explanation:
Equation: 68.50=48+5x
It is 28 i think been 3 year since i did this
A = 1 and 8
B = 2 and 4
C = 2 and 7
I’m pretty sure this is right? I’m still learning too :p

NOTE:
The Statement is what was provided, Reason is the justification (proof), Side Note is JUST FOR YOU so you understand why the answer for the Reason was chosen.