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aniked [119]
3 years ago
11

Write an inequality that expresses the range in the volume of acceptable tennis balls.

Mathematics
1 answer:
Rudik [331]3 years ago
4 0

Answer:

the smallest number is the lower bound and the largest number is the upper bound, your inequality would be

8.2 ≤ x ≤ 9.5, where x represents the volume of tennis balls.

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An indoor sport exhibition is coming to the arena. Your supervisor has asked you to help set up a handball pitch and seating are
Sphinxa [80]

Answer:

Perimeter: 174.8 m

Area: 1,394 sq m

Step-by-step explanation:

First, the perimeter.

Before we start, let's calculate the circumference of the half-circles at the ends of the field.

The measurement says 2,000 cm, so let's convert it to 20 m for ease.

Circumference of a circle: πd, where d = diameter.. in our case d = 20 m

Circumference of a 20m diameter circle: 20π = 62.8 m

We have 2 half circles... so the perimeter of each half-circle will be: 31.4 m

We also have 800 cm measurement for the "height" of the seating areas... let's convert that in 8 m

We also need to find out the space between the seating area...  We know the whole rectangular pitch is 40 m, then we have to subtract the width of both seating areas (20 and 15 m)... so the space between them is 5m

So, starting with the upper left corner of the rectangular pitch, and working our way clockwise, we encounter the following lengths:

P = 40 + 31.4 + 8 + 10 + 8 + 5 + 8 + 25 + 8 + 31.4 = 174.8 m

The total perimeter is then of 174.8 m

For the area, we need to calculate the area of all forms:

Large rectangular pitch:

LR = 40 x 20 = 800 sq m

The two half circles, form a circle, so A = πr², where r is the radius, which is half the diameter.

AC = π (10)² = 100 π = 314 sq m

Then the seating areas:

SA1 = 25 x 8 = 200 sq m

SA2 = 10 x 8 - 80 sq m

Then, we add up everything:

TA = LR + AC + SA1 + SA2

TA = 800 + 314 + 200 + 80 = 1,394 sq m

3 0
3 years ago
∆ABC is an isosceles triangle. The length of CB is 12 feet 4 inches and the congruent sides are
son4ous [18]

Answer:

Answer for 2nd is option c, for 3rd is option d, for 4th is option e

Step-by-step explanation:

As we know 1 ft.=12 in.

  1. In ΔABC

   ∴ The congruent sides are AB and AC respectively

  • CB =12 ft. 4 in.=148 in.
  • AB=\frac{3}{4}CB =111 in. =9 ft. 3 in.
  • AC=\frac{3}{4}CB =111 in. =9 ft. 3 in.

    ∵  <em>Perimeter of ΔABC</em> =AB+AC+CB

                                        =9 ft. 3 in. + 9 ft. 3 in. +12 ft. 4 in.

                                        =30 ft. 10 in.

    2. In ΔDEF

    ∴ The congruent sides are DE and DF respectively

  • DE =  6 ft. 3 in. =75 in.
  • DF =  6 ft. 3 in. =75 in.
  • Let the length of FE is equal to x
  • 0.75FE =DE =DF
  • 0.75x = 6 ft. 3 in. =75 in.
  • x =100 in. =8 ft. 4 in.

   ∵ <em>Perimeter of ΔDEF</em> =DE+DF+FE

                                        = 6 ft. 3 in. +6 ft. 3 in. +8 ft. 4 in.

                                        = 20 ft. 10 in.

    3. In ΔJKL

    ∴ The congruent sides are JL and KL respectively

  • JK = x+3
  • KL =4x-17
  • JL  =6x-45
  • JL≅KL
  • 4x-17 =6x-45  . . . . . . . . . . . . . . . . . . . . . . . (1)
  • Subracting 4x from both sides from eq 1
  • -17 =2x-45
  • Adding 45 on both the sides
  • 28 =2x
  • Dividing by 2 on both sides
  • 14 =x
  • JK = 14+3 =17
  • KL = 4×14-17 =39
  • JL = 6×14-45 =39

   ∵ <em>The dimensions of the ΔJKL are 39,39 and 17.</em>

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The total will be $6,360.
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