Use the graphing calculator to graph the quadratic function y= 2x + 2x- 40. What are the zeros of the function?
1 answer:
Answer:
The answer is 4 and -5.
Step-by-step explanation:
Working under the assumption that the first term is not 2x, but 2x², you can find the zero values by factoring the expression:
With it factored we can see that x being equal to -5 or 4 will give a zero value
Let's also see it plotted, as the question said to use a graphing calculator:
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Answer:
f(x) = -5x +48
Step-by-step explanation:
A fairly easy way to write the equation of the perpendicular line is to swap the x- and y-coefficients, negating one of them. Then choose the constant in the equation to make it true at the given point.
<h3>Swapped coefficients</h3>In this instance, we find it convenient to leave the coefficient of y as positive.
5y = x -10 . . . . . . original equation
y = -5x +c . . . . . . with coefficients swapped, x-coefficient negated
<h3>New constant</h3>At the given point, the equation becomes ...
8 = -5(8) +c
48 = c . . . . . . . add 40
<h3>Equation of the perpendicular line</h3>The equation of the line is then ...
y = -5x +48
f(x) = -5x +48 . . . . . . in functional notation
