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schepotkina [342]
4 years ago
15

Use the graphing calculator to graph the quadratic function y= 2x + 2x- 40. What are the zeros of the function?

Mathematics
1 answer:
satela [25.4K]4 years ago
6 0

Answer:

The answer is 4 and -5.

Step-by-step explanation:

Working under the assumption that the first term is not 2x, but 2x²,  you can find the zero values by factoring the expression:

y = 2x^2 + 2x - 40\\y = 2(x^2 + x - 20)\\y = 2(x + 5)(x - 4)

With it factored we can see that x being equal to -5 or 4 will give a zero value

Let's also see it plotted, as the question said to use a graphing calculator:

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Step-by-step explanation:

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Find all the zeros of f(x).
Vitek1552 [10]

Answer:

The zeroes are -6, 1/2 and 2.

Step-by-step explanation:

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So substituting x = 2:

f(2) = 16+ 28 - 56 + 12 = 0

So x = 2 is a zero and x - 2 is a factor of f(x)

Performing long division:

x - 2)2x3 + 7x2 - 28x + 12( 2x2 + 11x - 6 <------- Quotient

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                 11x2 - 28x

                 11x2 - 22x

                          - 6x + 12

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                            .............

Now we solve

2x2 + 11x - 6 = 0

(2x - 1)(x + 6) = 0

2x - 1 = 0 or x + 6 = 0, so:

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Answer:

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Step-by-step explanation:

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