Answer:
Theo worked for 12 hours and Kade worked for 15
Step-by-step explanation:
if kade worked for 10 hours Theo works for 7 so in total they worked for 17 hours together. So what you do is you just continue counting kades hours, subtracting 3 then add those number together till you get the total of 27 hours.
Answer:
i think y = 5 is answer
Step-by-step explanation:
good luck
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Answer:
2n(8n + 5)
Step-by-step explanation:
you need to see what you can take out of both the numbers.
ex they both have an 'n' and they both are divisible by 2
Answer:
<u>n < -13</u>
Step-by-step explanation:
n - 16 < -29
n -16 + 16 < -29 + 16
n < -13
if you want n as an ordered pair it would be : n = (-14 , negative infinity)
I hope this helps..
Good luck :)
