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3 years ago

In what way is cellular respiration like breathing?

Chemistry

1 answer:

Oxana [17]3 years ago

7 0

Answer:Cellular respiration is not the same as breathing, but they are closely related

Explanation: When you breathe in, you take in the oxygen your cells need for cellular respiration. When you breathe out, you get rid of carbon dioxide that your cells produce during cellular respiration.

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Równania reakcji chemicznej

Aliun [14]

Answer:

Reakcja chemiczna jest opisana równaniem chemicznym, wyrażeniem określającym tożsamość i ilość substancji biorących udział w reakcji. Równanie chemiczne pokazuje początkowy związek (związki) - reagenty - po lewej stronie, a końcowy związek (związki) - produkty - po prawej stronie, oddzielone strzałką.

Explanation:

5 0

4 years ago

Phosgene, a poisonous gas, when heated will decompose into carbon monoxide and chlorine in a reversible reaction: COCl2 (g) <

Advocard [28]

Answer:

8.08 × 10⁻⁴

Explanation:

Let's consider the following reaction.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

The initial concentration of phosgene is:

M = 2.00 mol / 1.00 L = 2.00 M

We can find the final concentrations using an ICE chart.

COCl₂(g) ⇄ CO (g) + Cl₂(g)

I 2.00 0 0

C -x +x +x

E 2.00 -x x x

The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.

The concentrations at equilibrium are:

[COCl₂] = 2.00 -x = 1.96 M

[CO] = [Cl₂] = 0.0398 M

The equilibrium constant (Keq) is:

Keq = [CO].[Cl₂]/[COCl₂]

Keq = (0.0398)²/1.96

Keq = 8.08 × 10⁻⁴

4 0

4 years ago

Given the balanced ionic equation:

bezimeni [28]

Answer : The correct option is, (4) 6.0 mol

Explanation :

The given balanced chemical equation is,

$3Pb^{2+}+2Cr\rightarrow 3Pb+2Cr^{3+}$

In this reaction, lead undergoes reduction and chromium undergoes oxidation.

Oxidation reaction : It is the reaction in which a substance looses its electrons. In this oxidation state increases.

Reduction reaction : It is the reaction in which a substance gains electrons. In this oxidation state decreases.

Half reactions of oxidation-reduction are :

Oxidation : $2Cr\rightarrow 2Cr^{3+}+6e^-$

Reduction : $3Pb^{2+}+6e^-\rightarrow 3Pb$

From the reduction reaction, we conclude that 6 moles of electrons gained by the 3 moles of lead ions.

Hence, the correct option is, (4) 6.0 mole

5 0

3 years ago

You have 41.6 g of O2 gas in a container with twice the volume as one with CO2 gas in another container. The pressure and temper

prisoha [69]

Answer:

The mass of carbon dioxide is 28.6 grams

Explanation:

Step 1: Data given

Mass of O2 = 41.6 grams

Volume of the O2 container = 2V

Volume of the CO2 container = V

Pressure and temperature are the same

Step 2: Ideal gas law

The ideal gas law = p*V=nRT

For O2: p*2V = n(O2)*R*T

For CO2: p*V = n(CO2)*R*T

n(O2)*R*T / P*2V = n(CO2)*R*T / P*V

Since P, R and T are contstant, we can simplify this to:

n(O2)/2 = n(CO2)

Step 3: Calculate moles of O2

Moles O2 = mass O2/ Molar mass O2

Moles O2 = 41.6 grams / 32 g/mol

Moles O2 = 1.3 mol O2

The number of moles CO2 = 0.65 mol

Mass of CO2 = Moles CO2 * Molar Mass CO2

Mass of CO2 = 0.65 mol * 44.01 g/mol

Mass of CO2 = 28.6 grams

The mass of carbon dioxide is 28.6 grams

5 0

4 years ago

How many moles of acetylene are needed to completely react with 16.5g of CO2

kykrilka [37]

Answer:

0.375 mols

Explanation:

Relative atomic mass Ar of C=12×1=12
Relative atomic mass Ar of O=16×2=32
Realitive formula mass Mr is 12+32=44

mol:mass

1 : 44

x :16.5

cross multiply and get the answer

5 0

3 years ago