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cluponka [151]
3 years ago
6

Help me ASAP I really need it

Mathematics
2 answers:
Natali5045456 [20]3 years ago
7 0

Answer:

1000

Step-by-step explanation:

Gekata [30.6K]3 years ago
4 0
1000 is ur answer!! :)
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Find all the numbers such that the number added to itself is less than the number subtracted from 6
gizmo_the_mogwai [7]

Answer:

All numbers less than 2 or (-\infty, 1] or (-\infty, 2)

Step-by-step explanation:

Given that:

Number is added to itself is less than the number subtracted from 6.

To find:

All such numbers.

Solution:

Let the number be x.

Here, an inequality will be made.

When solved, it might give more than one answers.

As per the question statement, let us write the inequality.

Number added to itself \Rightarrow x +x =2x

Number subtracted from six = 6-x

As per question:

2x

So, the answer is:

All numbers less than 2 or (-\infty, 1] or (-\infty, 2).

4 0
3 years ago
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