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3 years ago

Please help me the first person gets brainlest

Mathematics

2 answers:

HACTEHA [7]3 years ago

7 0

Answer:

“Help with what?“

Step-by-step explanation:

mylen [45]3 years ago

4 0

Answer:

did you forget the pic?

Step-by-step explanation:

You might be interested in

Find the annual interest rate.

slega [8]

The annual interest rate is 3.5%.

Solution:

Given Interest (I) = $26.25

Principal (P) = $500

Time (t) = 18 months

Rate of interest (r) = ?

Time must be in years to find the rate per annum.

1 year = 12 months

Divide the time by 12.

Time (t) = $\frac{18}{12}=\frac{3}{2}$ years

Now, find the rate of interest using simple interest formula.

<u>Simple interest formula:</u>

$$I=\frac{Prt}{100}$

$$26.25=\frac{500\times r\times \frac{3}{2} }{100}$

$$26.25\times 100 =500\times r\times \frac{3}{2}$

$$2625 =250\times r\times 3$

$$2625 =750\times r$

$$\Rightarrow r=\frac{2625}{750}$

⇒ r = 3.5%

Hence the annual interest rate is 3.5%.

8 0

3 years ago

The answer pleaseeeeeeeeee

ArbitrLikvidat [17]

The answer is B, 5+7=12. You can also just subtract 5 from 12 and that’ll also give you the answer

8 0

3 years ago

Read 2 more answers

Consider a population consisting of the number of teachers per college at small 2-year colleges. Suppose that the number of teac

agasfer [191]

Answer:

a) $\frac{8}{9}$ =0.89

b) 0.8413

Step-by-step explanation:

we know that

$P(║ x -\mu║ \leq k\sigma) \geq 1 -\frac{1}{k^2}$

$so, \mu = 150, \sigma = 20$

$k = \frac{210 - 150}{20} =\frac{150 - 90}{20} = 3$

$P(║ x -150 ║ \leq 3\times 20) \geq 1 -\frac{1}{3^2} = \frac{8}{9}$

x - N(150, 20^2)

$P(X \leq 170) = 0.8413447$

check

$P norm = \frac{170 - 150}{20}= 0.8413447$

8 0

3 years ago

A phone company advertises a new plan in which the customer pays a fixed amount of $25 per month for unlimited calls in the coun

GarryVolchara [31]

Answer 750$ becaus jfhfhfhfhfhfhfhfhfhfh

8 0

2 years ago

Read 2 more answers

The value of y varies directly as the square of x and y=27 when x=9. Find the equation represents this relationship. Report the

skad [1K]

Answer:

The relation between x and y is

$y=\frac13 x^2$

Step-by-step explanation:

Given that,

The value of y varies directly as the square of x.

$y\propto x^2$

$\Rightarrow y=rx^2$

where r is constant of proportional.

Given that,

y= 27 and x=9

Plug y= 27 and x=9 in above relation

$y=rx^2$

$\therefore 27=r(9)^2$

$\Rightarrow 27 = r.81$

$\Rightarrow r=\frac{27}{81}$

$\Rightarrow r=\frac{1}{3}$

The relation between x and y is

$y=\frac13 x^2$

8 0

3 years ago