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3 years ago

on a map 5 inches repents. 100 miles. how many inches would. there be between. two cites that are 2,500 miles apart

Mathematics

1 answer:

suter [353]3 years ago

3 0

Answer:

500 miles

Step-by-step explanation:

2,500 divided by 5 = 500

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Answer:

(a) The mean or expected value of X is 2.2.

(b) The standard deviation of X is 1.3.

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Let X = number of times the traffic light is red when a commuter passes through the traffic lights.

The probability distribution of X id provided.

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$\mu=E(X)=\sum x.P(X=x)$

The formula to compute the standard deviation of X is:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}$

The formula of E (X²) is:

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(a)

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Thus, the mean or expected value of X is 2.2.

(b)

Compute the value of E (X²) as follows:

$E(X^{2})=\sum x^{2}.P(X=x)\\=(0^{2}\times0.06)+(1^{2}\times0.25)+(2^{2}\times0.35)+(3^{2}\times0.15)+(4^{2}\times0.13)+(5^{2}\times0.06)\\=6.58$

Compute the standard deviation of X as follows:

$\sigma=\sqrt{E(X^{2})-(E(X))^{2}}\\=\sqrt{6.58-(2.22)^{2}}\\=\sqrt{1.6516}\\=1.285\\\approx1.3$

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3 years ago

on a map 5 inches repents. 100 miles. how many inches would. there be between. two cites that are 2,500 miles apart​

on a map 5 inches repents. 100 miles. how many inches would. there be between. two cites that are 2,500 miles apart