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Dahasolnce [82]
2 years ago
5

The legs of a right triangle are x + 1 and x + 4. What is the area of the triangle?

Mathematics
1 answer:
Dominik [7]2 years ago
5 0

Answer:

(x^2 + 5x + 4) : 2

Step-by-step explanation:

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Y = 5x + 7<br> 2x + y = -5<br> Are the equations parallel,<br> perpendicular, or neither?
Nezavi [6.7K]

Lines are neither perpendicular nor parallel.

Step-by-step explanation:

Step 1:

In equation 1, Y = 5X + 7

In equation 2,  Y = -2X -5

Step 2:

Slope Intercept form Y =mX +c

Where m = Slope

Slope of line 1 = 5

Slope of line 2 = -2

m1  is not equal to m2. Hence it is not parallel.

m1  × m2 is not equal to -1. Hence they are not perpendicular.

3 0
3 years ago
In your lab, a substance's temperature has been observed to follow the function T(x) = (x + 5)3 + 7. The turning point of the gr
kompoz [17]
A turning point occurs when the velocity is equal to zero, but the acceleration is not equal to zero. 

t(x)=(x+5)^3+7

dt/dx=3(x+5)^2

d2t/dx2=6(x-5)

dt/dx=0 only when x=-5

However, since d2t/dx2(-5)=0, this point is an inflection point, not a turning point.

So there is no turning point for this function.

Now in this problem, it is even easier than the above to show that there is no turning point.  A turning point by definition is when the derivative or velocity changes sign.  Since in this case v=3(x+5)^2, for any value of x, v≥0, and thus never becomes negative, so it never changes from a positive to negative velocity because velocity in this instance is a squared function.


8 0
3 years ago
Identify the volume and surface area of the hemisphere in terms of π. HELP ASAP!!
posledela

Answer:

D

Step-by-step explanation:

Use the formula for the SA of a hemisphere.

SA=2\pi r^2

Now we can find the radius of the hemisphere, which is 15.

Then, we can square that and multiply it by 2 to get 450.

Now, let's use the formula for the Volume of a hemisphere.

V=\frac{2\pi r^3}{3}

Now we can cube 15 and multiply it by 2 to get 6750.

Then we can divide this number by 3.

2250.

So the answer is D.

4 0
3 years ago
. Use the quadratic formula to solve each quadratic real equation. Round
Liono4ka [1.6K]

Answer:

A. No real solution

B. 5 and -1.5

C. 5.5

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}, with a being the x² term, b being the x term, and c being the constant.

Let's solve for a.

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {5^2 - 4\cdot1\cdot11} }}{{2\cdot1}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {25 - 44} }}{{2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 5 \pm \sqrt {-19} }}{{2}}} \end{array}

We can't take the square root of a negative number, so A has no real solution.

Let's do B now.

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {7^2 - 4\cdot-2\cdot15} }}{{2\cdot-2}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {49 + 120} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm \sqrt {169} }}{{-4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 7 \pm 13 }}{{-4}}} \end{array}

\frac{7+13}{4} = 5\\\frac{7-13}{4}=-1.5

So B has two solutions of 5 and -1.5.

Now to C!

\begin{array}{*{20}c} {\frac{{ -(-44) \pm \sqrt {-44^2 - 4\cdot4\cdot121} }}{{2\cdot4}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm \sqrt {1936 - 1936} }}{{8}}} \end{array}

\begin{array}{*{20}c} {\frac{{ 44 \pm 0}}{{8}}} \end{array}

\frac{44}{8} = 5.5

So c has one solution: 5.5

Hope this helped (and I'm sorry I'm late!)

4 0
3 years ago
What is the supplement of 123°
makkiz [27]
Since (x - 2)° and (2x + 5)° represent a pair of supplementary angles, then their sum must be equal to 180°. Therefore, the two supplementary angles are 57° and 123°.
8 0
3 years ago
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