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3 years ago

I really need help with this thing for math it is due today help me if yall know this

Mathematics

1 answer:

Yuri [45]3 years ago

5 0

Answer:

Step-by-step explanation:

Trust.

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Choose the statistical question. * please help now

Oliga [24]

Answer:

*me sweating while answering this*

Step-by-step explanation:

i think my dogs weigh about 50 pounds each

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4 0

3 years ago

Complete the remainder of the table for the given function rule:

USPshnik [31]

answer is

(Y)=-23,-14, -5,4,13

hope this will help you

3 0

3 years ago

Which of the following absolute value equations has no solutions?Group of answer choices

Amiraneli [1.4K]

The absolute value measures the distance a number is away from the origin (zero) on the number line. A number can be to the left or right of zero on the number line, but the distance away from zero is always positive. Graphically:

In other words:

• If d is positive and

$\begin{gathered} |x|=d \\ \text{ then} \\ x=d\text{ or }x=-d \end{gathered}$

• If d is negative and

$\begin{gathered} |x|=-d \\ \text{then} \\ \text{ No solution, because distance (d) can not be negative.} \end{gathered}$

Therefore, the equation that has no solutions is:

$\boldsymbol{|x|=-3}$

3 0

1 year ago

Find the distance between the points of intersection of the graphs of the functions.

Viefleur [7K]

Answer:

Find the value of x and y in coordinate form, that'll be the point of intersection.

Question 1

${ \rm{y = {x}^{2} - 3x + 4 }} \\ { \boxed{ \tt{but \: y = x + 1 \: }}} \\ \\ { \rm{(x + 1) = {x}^{2} - 3x + 4 }} \\ \\ { \rm{ {x}^{2} - 4x + 3 = 0 }} \\ \\ { \rm{(x - 3)(x - 1) = 0}} \\ \\ { \boxed{ \rm{x_{1} = 3 \: \: and \: \: x _{2} = 1}}} \\ \\ { \boxed{ \tt{remember \: y = x + 1}}} \\ \\ { \rm{y _{1} = 4 \: \: and \: \: y _{2} = 2 }}$

Therefore, points of intersection are two

Answer:  (3, 4) and (1, 2)

Question 2:

Following the steps as in question 1

${ \rm{y = {x}^{2} - 4}} \\ \\{ \rm{2x - 4 = {x}^{2} - 4}} \\ \\ { \rm{ {x}^{2} = 2x }} \\ \\ { \boxed{ \rm{x = 2}}} \\ { \tt{remember : \: y = 2x - 4 }} \\ { \boxed{ \rm{y = 0}}}$