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Rina8888 [55]
3 years ago
13

A sphere has a radius of 3 and a hemisphere has a radius of 6. Compare the ratio of the volume of the sphere to the volume of th

e hemisphere.
Mathematics
2 answers:
Trava [24]3 years ago
8 0
S=(4πr^3)/3, H=(4πr^3)/6

S/H=2rs^3/rh^3

S/H=(2*3^3)/6^3

S/H=54/216

S/H=1/4

So the volume of the hemisphere is 4 time the volume of the sphere.
mixas84 [53]3 years ago
3 0
Volume of a sphere:
V=4/3 π r³

V=4/3 π 3³ = <span>113.097335529
</span>
Volume of a Hemisphere:
V=½(4/3 π r³)

V=½(4/3 π 6³) = <span>452.389342117
</span>
113.097335529 to 452.389342117

Pretty much 1/4 right on the nuts (0.24999999999944737866981989309472)
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Assume I created a 95% confidence interval for the mean hours studied for a test based on a random sample of 64 students. The lo
CaHeK987 [17]

Answer:

(a) Width = 15.4866.

(b) Margin of error = 7.7433.

(c) Center = 10.8849.

(d) Sample mean = 10.8849.

(e) <em>z</em> = 1.96.

(f) Population standard deviation = 31.6053.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population mean when the population standard deviation is known is:

CI=\bar x\pm z_{\alpha/2}{\frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the mean hours studied for a test is (3.1416, 18.6282).

The sample taken was of size, <em>n</em> = 64.

(a)

Compute the width of the interval as follows:

Width=Upper\ limit-Lower\ limit\\=18.6282-3.1416\\=15.4866

Thus, the width of the confidence interval is 15.4866.

(b)

Compute the margin of error of the interval as follows:

MOE=\frac{Width}{2}=\frac{15.4866}{2}=7.7433

Thus, the margin of error of the confidence interval is 7.7433.

(c)

Compute the center of the confidence interval as follows:

Center=\frac{Upper\ limit+Lower\ limit}{2}=\frac{18.6282+3.1416}{2}=10.8849

Thus, the center of the confidence interval is 10.8849.

(d)

The center of a (1 - <em>α</em>)% confidence interval is the value of the sample statistic.

In case of the confidence interval for population mean the center of the interval is the sample mean.

The value of sample mean is 10.8849.

(e)

For a 95% confidence interval the critical value of <em>z</em> is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table for the critical value.

Thus, the value of <em>z</em> is 1.96.

(f)

Compute the value of standard deviation as follows:

MOE=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}\\7.7433=1.96\times \frac{\sigma}{\sqrt{64}}\\\sigma=\frac{7.7433\times 8}{1.96}\\\sigma=31.6053

Thus, the value of population standard deviation is 31.6053.

7 0
4 years ago
F(x)=2x + 1 and g(x) = -3x+4. Find f(x) + g(x)
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To do this, simply add the 2 functions-as it says:

(2x+1) + (-3x+4)
2x+1-3x-4
-x-3

Your answer is -x-3
5 0
3 years ago
What’s the correct answer answer asap
barxatty [35]

Answer:

I believe the answer is B, it makes the most sense

Step-by-step explanation:

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2 years ago
I WILL GIVE YOU BRAINLIEST AND 20 POINTS, PLS HELP. K12 STUDENT.
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36, |-12|=12 and |-3|= 3. Using inverse operations, we multiply instead of dividing and get 36.

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4 years ago
How to do question 1?Had no idea how to do both parts
givi [52]
y=\dfrac{\ln x}{3x-6}

Differentiate both sides with respect to x:

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}

When x=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}=\dfrac{-3}9=-\dfrac13

For part (b), we now assume that x and y are functions of an independent variable, which we'll call t (for time). Now differentiating both sides with respect to t, we have

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{\frac{3x-6}x-3\ln x}{(3x-6)^2}\dfrac{\mathrm dx}{\mathrm dt}

where the chain rule is used on the right side. We're told that y is decreasing at a constant rate of 0.1 units/second, which translates to \dfrac{\mathrm dy}{\mathrm dt}=-0.1. So when x=1, you have

-0.1=\dfrac{\frac{3-6}1-3\ln1}{(3-6)^2}\dfrac{\mathrm dx}{\mathrm dt}
-0.1=-\dfrac13\dfrac{\mathrm dx}{\mathrm dt}
\dfrac{\mathrm dx}{\mathrm dt}=0.3

where the unit is again units/second.
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3 years ago
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