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3 years ago

Reciprocal of 11/18

Mathematics

2 answers:

jonny [76]3 years ago

8 0

Answer:

18/11

Step-by-step explanation:

To get the reciprocal all you do is flip over the fraction <3

Sveta_85 [38]3 years ago

5 0

I’m like 90% sure it’s just 18/11 you just flip the numbers around

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Z-(-3/4)= 6 1/2 I need help quick

liraira [26]

If Z is the unknown, then
Z-(-3/4)= 6 1/2
Z+3/4= 6 1/2
Z= 6 1/2 - 3/4
Z= 23/4 = 5 3/4

7 0

3 years ago

Question below

Ksivusya [100]

Answer:

$m \times H=\left[\begin{array}{c c c}\boxed{-9} & \boxed{36} & \boxed{-\dfrac{9}{2}}\end{array}\right]$

Step-by-step explanation:

<u>Calculate the value of m</u>

Given:

$3\left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]=\dfrac{2}{3}m \times \left[\begin{array}{c c}-1 & 2 \\4 & 8\end{array}\right]$

Therefore:

$\implies 3=\dfrac{2}{3}m$

$\implies m=3 \times \dfrac{3}{2}$

$\implies m=\dfrac{9}{2}$

<u>Calculate the value of H</u>

Given:

$\left(H+ \left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]\right)+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]=\left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]+\left(\left[\begin{array}{c c c}1 & 4 & -2\end{array}\right]+\left[\begin{array}{c c c}3 & 2 & -6\end{array}\right]\right)$

Therefore:

$\implies H= \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]$

<u />

<u>Calculating m × H</u>

<u />

<u /> $\implies m \times H=\dfrac{9}{2} \times \left[\begin{array}{c c c}-2 & 8 & -1\end{array}\right]$

<u /> $\implies m \times H=\left[\begin{array}{c c c}\dfrac{9}{2}(-2) & \dfrac{9}{2}(8) & \dfrac{9}{2}(-1)\end{array}\right]$

$\implies m \times H=\left[\begin{array}{c c c}-9 & 36 & -\dfrac{9}{2}\end{array}\right]$ <u />

7 0

2 years ago

Work out the value of (1.7*10^4)*(8.5*10^-2). give oyur answer in standard form

Readme [11.4K]

Answer:

14.45*10^6

Step-by-step explanation:

(1.7*10^4)*(8.5*10^2)=14.45*10^6

6 0

3 years ago

A company that manufactures computer components has a 3% defective rate. If 10 components are randomly selected, find the probab

deff fn [24]

Answer:

The probability of getting 2 defective items

P(X=2) = 0.0317416

Step-by-step explanation:

Given that size of the components n = 10

Given that the probability of getting the defective item

p = 3% = 0.03

q = 1-p =1- 0.03 = 0.97

Let 'X' be a random variable in a binomial distribution

$P(X=r) =n_{C_{r} } p^{r} q^{n-r}$

The probability of getting 2 defective items

$P(X=2) =10_{C_{2} } (0.03)^{2} (0.97)^{10-2}$

$10_{c_{2} } = \frac{10!}{(10-2)!2!} = \frac{10 X 9 X8!}{8!2!} = 45$

P(X =2) = 45 × 0.000705

P(X=2) = 0.0317416

5 0

3 years ago

Please no links!!<br><br>and please help me

AURORKA [14]

Answer:

Hey mate....

Step-by-step explanation:

This is ur answer....

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Hope it helps!

Brainliest pls!

Follow me! ♧

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2 years ago