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nignag [31]
3 years ago
5

Help. Does anyone know the answer. Pls help!

Mathematics
2 answers:
sdas [7]3 years ago
6 0

Answer:

Step-by-step explanation:

the first and last choices look good  

Jobisdone [24]3 years ago
6 0
The first one ^^^^^^^^^
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Can someone help with B please.
yawa3891 [41]
X + 5
———
3x+2

Steps:

Factor 3x^2 + 13x - 10: (3x -2)(x + 5)
(3x -2)(x+5)
= —————
9x^2 - 4

Factor 9x^2 - 4 (3x - 2)(3x-2)
8 0
3 years ago
X is at most 30 represent as an algebraic inequality
masya89 [10]

Answer:

x ≤ 30

Step-by-step explanation:

'at most' means the same as 'less than or equal to'.

The sign 'for less than or equal' to is ≤.

So it's simply x ≤ 30.

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=4y%20%2B%208%20%3D%202" id="TexFormula1" title="4y + 8 = 2" alt="4y + 8 = 2" align="absmiddle"
soldi70 [24.7K]

4y+8=2\qquad|\text{subtract 8 from both sides}\\\\4y=-6\qquad|\text{divide both sides by 4}\\\\y=-\dfrac{6}{4}\\\\\boxed{y=-\dfrac{3}{2}\to y=-1.5}

8 0
4 years ago
Read 2 more answers
HELP FAST<br><br> WILL MAKE BRAINLIEST
valkas [14]

Answer:

x = 0.357143

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

Step-by-step explanation:

<u>Step 1: Define</u>

-1.6 - 2x = 5x + 0.9

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 2x on both sides:                    -1.6 = 7x + 0.9
  2. Subtract 0.9 on both sides:           2.5 = 7x
  3. Divide 7 on both sides:                  0.357143 = x
  4. Rewrite:                                           x = 0.357143
8 0
3 years ago
The following data values represent a sample. What is the variance of the sample? X=9. Use the information in the table to help
babunello [35]

Answer: it’s 28 for sure

Step-by-step explanation:

3 0
3 years ago
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