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3 years ago

-31,-22,-33 find the 35th term

Mathematics

1 answer:

Karo-lina-s [1.5K]3 years ago

8 0

Answer:

easy bro go and use m-a-t-h w-a-y

Step-by-step explanation:

it's going to help

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

guajiro [1.7K]

Answer:

5 - x

Step-by-step explanation:

Given:

$f(x)=25-x^2$

$g(x)=x+5$

$\begin{aligned}\left(\dfrac{f}{g}\right)(x) & = \dfrac{f(x)}{g(x)}\\\\ & = \dfrac{25-x^2}{x+5}\\\\& = \dfrac{(5-x)(5+x)}{(x+5)}\\\\& = \dfrac{(5-x)(x+5)}{(x+5)}\\\\& = 5-x\end{aligned}$

8 0

2 years ago

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Would like to know Is -6.06 a integers

horrorfan [7]

Answer:

An integer is a whole number (not a fractional number) that can be positive, negative, or zero.

Since it's a decimal it can not be an integer.

6 0

2 years ago

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This question is kind of confusing and i need help, please and thank you! :)

solong [7]

ummmmmmmm a lot and alot

6 0

2 years ago

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Look at the graph below: First line joins ordered pairs negative 4, 3 and 2, negative 3. Second line joins negative 4, negative

slavikrds [6]

Answer:

Part B shaded below first line and above second line.

Step-by-step explanation:

The first inequality corresponds to the second line (-3 = -4+1, for example) The ≥ symbol in that inequality tells you it will be satisfied by y values above those on the line.

The second inequality corresponds to the first line (-4+3 = -1, for example) The ≤ symbol in that inequality tells you it will be satisfied by y values below those on the line.

Hence the solution set is those values shaded below the first line and above the second line — matching Part B.

8 0

3 years ago

Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object

vovikov84 [41]

(a)

We can see that

this is a straight line

and this is the graph of velocity

we know that

acceleration is the derivative of velocity

so, slope of curve of velocity is acceleration

so, we will find slope of this line

We can select any two points

(0,4) and (5,7)

we can use slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug points

$m=\frac{7-4}{5-0}$

$m=0.6$

we know that slope of line is always constant irrespective of any value of t

so, acceleration will always be same irrespective of any value of t

so, we will get acceleration

$a(t)=0.6m/s^2$ ............Answer

(b)

we can see that acceleration is constant

and we know that

derivative of constant is always 0

so, instantaneous rate of acceleration at t=10s is 0........Answer

7 0

3 years ago

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