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alina1380 [7]
3 years ago
12

CAN SOMEONE PLEASE HELP ME WITH THESE!!!

Mathematics
2 answers:
kolbaska11 [484]3 years ago
6 0
Idek

Sorry
And I’m just answering for the person who posted can give brainlist to the other person
So hopes this helps
Darya [45]3 years ago
3 0

Answer:

for the first pic

1=133

2=47

3=47

4=133

5=133

6=47

7=47

8=133

the next pic

2,3 is a corresponding angle

1,2 is a verticle angle

the third pic

1=153

2=27

Step-by-step explanation:

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Y = x² – 4 y = 2r + 4​<br><br>Solve algebraicallu for the solutions of equations below.
oksano4ka [1.4K]

Step-by-step explanation:

Okay, the first step is to rewrite this equation in "vertex form." You can search that up but it's basically just (h/k).

y = ( x − 1) 2 + 3

Now, we are going to use the vertex form, "y = a (x - h)2 + k, to get the values of a, h, and k.

By using the form we get 1 for the value a, 1 for the value h, and 3 for the value k.

1 = a

1 = h

3 = k

Becuse the value of a is positive, the parabola opens up!  (A parabola is the U shaped line in a graph, so that opens up.)

Now, we find the vertex (h,k)

which is (1,3)

Now we find the p from the vertex to the focus.  (vertext the top, focus one of the points.)

Follow this formula to find the distance from the vertex to a focus by using this formula

1/4a.

Now we just gonna substitue 1 for a, since we know that 1 equals a above ^

1/4 * 1

Solving that, we got a nice little 1/4.

Next we find the focus

"Find the focus.

The focus of a parabola can be found by adding p to the y-coordinate k if the parabola opens up or down.

(h,k+p)

Substitute the known values of h, p, and k into the formula and simplify.

(1,134)

Find the axis of symmetry by finding the line that passes through the vertex and the focus.

x=1

Find the directrix.

y=114

Use the properties of the parabola to analyze and graph the parabola.

Direction: Opens Up

Vertex: (1,3)

Focus: (1,134)

Axis of Symmetry: x=1

Directrix: y=114

Select a few x values, and plug them into the equation to find the corresponding y values. The x values should be selected around the vertex.

xy−1704132437

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex: (1,3)

Focus: (1,134)

Axis of Symmetry: x=1

Directrix: y=114

xy−17041324"

(Sorry if this is long! But I hope you understand it better now! Thanks for the points!)

3 0
3 years ago
Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN
MrRa [10]

Since the distance of MN is 31 and we have a distance of ML of h -15 and LN of 2h – 8, therefore

ML + LN = h -15 + 2h – 8 = 31

 h = 18

substituting the value of h to the expression for LN obtaining

 

LN = 2h – 8

LN = 2(18) – 8

LN = 28

 

Therefore the length of the segment LN is 28 units

7 0
3 years ago
What is the gradient and y-intercept of a<br> line with equation y = 3x+2?
Diano4ka-milaya [45]
Gradient:3
Y intercept:(0,2)
8 0
3 years ago
Score: 0 of 1 pt
Sholpan [36]

Answer:

26x+6

Step-by-step explanation:

because i am really smart

6 0
3 years ago
Find the ratio and unit rate.<br> 216 cherry pieces in 6 bags of candy
Charra [1.4K]

Answer:

216:6 ratio

36 rate

Step-by-step explanation:

3 0
3 years ago
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