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3 years ago

Find the gradient of the line segment between the points (2,5) and (1, -6)

Mathematics

1 answer:

MA_775_DIABLO [31]3 years ago

6 0

Hdhdbfjfjfdfndndhdjdhdhddhhddhhfd

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Please! help and tell me the answers, or help me figure out these answers for 20 points? please! And please help me. Can anybody

max2010maxim [7]

Answer:

1. Pattern (rule) : y = x-6

2. Pattern (rule) : y=x^2+1

3. Pattern (rule) : y = -3x

4. Pattern (rule) : y = 2x-2

5. Pattern (rule) : y = x^2

Step-by-step explanation:

Note: question number correspond to your order of questions.

1. Pattern (rule) : y = x-6

for missing parts, see attached table.

2. Pattern (rule) : y=x^2+1

3. Pattern (rule) : y = -3x

4. Pattern (rule) : y = 2x-2

5. Pattern (rule) : y = x^2

5 0

3 years ago

Can someone answer this question please answer it correctly if it’s corect I will mark you brainliest

schepotkina [342]

Answer:

1/9

Step-by-step explanation:

The possible choices 2,3,4

odd numbers: 3

P (odd number) = number of odd numbers /total

= 1/3

Then we spin again

The possible choices 2,3,4

We want a 3: 3

P (3) = number of 3's /total

= 1/3

Since the first spin did not affect the second spin

P(odd, then 3) = P(odd) *P( 3)

= 1/3* 1/3

=1/9

3 0

4 years ago

Bella's Pizza Shop charges $4.50 for a small pizza, $7 for a medium pizza, and $9 for a large pizza. Toppings cost extra dependi

rusak2 [61]

The unit price of each topping is $1.40. Divide $12.60 by the 3 toppings. That will give you the price of all 3 toppings together which is $4.20. Divide $4.20 by 3 and that will give you the unit price of each individual topping which is $1.40. To check your answer, multiply $1.40 by 3 which is $4.20. Then, multiply $4.20 by 3 which gives you the whole price which is $12.60

6 0

3 years ago

The sum of the reciprocal of two consecutive odd integers is 44/483.Write a rational equation to solve the problem.

Arturiano [62]

Answer:

Step-by-step explanation:

Let consecutive odd integers be (2x + 1) and (2x + 3)

Their reciprocals are $\frac{1}{2x + 1 }$ and $\frac{1}{2x + 3 }$

$\frac{1}{2x+1}+\frac{1}{2x+3}=\frac{44}{483}\\\\\frac{1*(2x+3)}{(2x+1)(2x+3)}+\frac{1*(2x+1)}{(2x+3)(2x+1)}=\frac{44}{483}\\\\\frac{2x + 3 + 2x +1}{(2x + 1)(2x+3)}=\frac{44}{483}\\\\\frac{4x + 4}{4x^{2}+8x+3}=\frac{44}{483}\\$

483*(4x+4) = 44*(4x² + 8x + 3)

483*4x + 483*4 = 44*4x² + 44*8x + 44*3

1932x + 1932 = 176x² + 352x + 132

176x² + 352x + 132 -1932x - 1932 = 0

Combine like terms

176x² + 352x - 1932x - 1932 + 132 = 0

176x² - 1580x - 1800 = 0

Divide the equation by 4

44x² - 395x - 450 = 0

8 0

3 years ago

CAN I HAVE HELLLLLLLPPPPPPP

uranmaximum [27]

Step-by-step explanation:

6t-13t+18t6t-13t+18t6t-13t+18t

4 0

3 years ago