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liq [111]
3 years ago
12

InWrite the equation of the line that passes through (7, - 4) and (- 1, 2) slope- intercept form.

Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer:

General Equation of a Line

General Equation \\(y - y_{1} )= m (x-x_{1}) \\Slope=m= \frac{x_{2}-x_{1} }{y_{2}-y_{1} } \\\\Given:\\p_{1}=(7,-4)\\p_{2}=(-1,2)\\Solution:\\m=(\frac{-1-7}{2-(-4)}) =\frac{-8}{6}\\y-(-4) = (\frac{-8}{6} )(x-7)\\y+4=\frac{-8x}{6} + 56\\y=\frac{-8x}{6} + 52 \\\\The\\  equation \\ is \\ y=\frac{-8x}{6} + 52

Step-by-step explanation:

Find the slope first and then place the values on the general formula. The final step is to solve for y

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C = -6

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Betty has 3 cats and 4 dogs. She feeds each of them one scoop of food
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What is the product of 1 2/3 and −3 1/2 ?
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8 0
3 years ago
Read 2 more answers
Compute the fare without tip: 1 passenger, 9.5 miles. Round to nearest fifth of a mile when dividing.
vladimir1956 [14]

The fare without tip for the Metro Taxi is of 1 passenger and 9.5 miles is $27.83.

The given parameters:

  • <em>Number of passenger = 1</em>
  • <em>Total distance = 9.5 miles</em>
  • <em>Cost of first 0.2 mile = $0.75</em>
  • <em>Cost of additional mile = $0.55</em>
  • <em>Cost of a passenger = $1.50</em>

The fare without tip for the Metro Taxi is calculated as follows;

  • for the first 0.2 mile = $0.75
  • the remaining distance = 9.5 - 0.2 = 9.3 miles

cost \ of \ distance = \$ 0.75 \ \ + \ \ \frac{\$ 0.55}{0.2 \ mile} \times 9.3 \ miles\\\\cost \ of \ distance =  \$ 26.325

Cost of 1 passenger = $1.50

The total cost is calculated as follows;

total cost = $1.50 + $26.325

total cost = $27.83

Thus, the fare without tip for the Metro Taxi is of 1 passenger and 9.5 miles is $27.83.

The complete question is below:

Compute the fare without tip: 1 passenger, 9.5 miles. Round to nearest fifth of a mile when dividing.

Metro Taxi: first 1/5 mi= $0.75, each additional 1/5 mi= $0.55, each additional passenger= $1.50.

Learn more about cost per miles here: brainly.com/question/2513267

8 0
3 years ago
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