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liq [111]
3 years ago
12

InWrite the equation of the line that passes through (7, - 4) and (- 1, 2) slope- intercept form.

Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer:

General Equation of a Line

General Equation \\(y - y_{1} )= m (x-x_{1}) \\Slope=m= \frac{x_{2}-x_{1} }{y_{2}-y_{1} } \\\\Given:\\p_{1}=(7,-4)\\p_{2}=(-1,2)\\Solution:\\m=(\frac{-1-7}{2-(-4)}) =\frac{-8}{6}\\y-(-4) = (\frac{-8}{6} )(x-7)\\y+4=\frac{-8x}{6} + 56\\y=\frac{-8x}{6} + 52 \\\\The\\  equation \\ is \\ y=\frac{-8x}{6} + 52

Step-by-step explanation:

Find the slope first and then place the values on the general formula. The final step is to solve for y

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Again this is a simple addition problem I think.

Add 3.6+4.705+5.92=

14.225 kilometers that Andrea ran over the three days.

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1935

Step-by-step explanation:

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2 years ago
What is (3x-4)^2 in expanded form
34kurt
(3x-4)(3x-4) is the answer because when something is squared, it's just multiplying itself by itself, this also applies to expressions.
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3 years ago
I can add fractions with unlike denominators. 2/5 + 3/10 =​
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Answer:

7/10

Step-by-step explanation:

2/5 multiply the denominator by 2 which will make it 10. Then multiply the numerator by 2 which will make it 4. So it will be 4/10. Then add 4/10 to 3/0 which makes 7/10.

6 0
2 years ago
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Arla and kal both work in jobs where they get paid by the hour in their first week on the job they each worked 40 hours and toge
valkas [14]

Question is Incomplete;Complete question is given below;

Arla and kal both work in jobs they get paid by the hour in their first week on the job they each worked 40 hours and together there total earnings were $1300 in their second week on the job business was slow so arla worked 20 hours and kal worked 16 hours their total pool earning was $580 what is each persons hourly wage.

Answer:

The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

Step-by-step explanation:

Let the hourly wage of Arla be 'x'

Also Let the hourly wage of Kal be 'y'

Now Given:

first week on the job they each worked 40 hours and together there total earnings were $1300

So we can say that;

40x+40y=1300   ⇒ equation 1

Also Given:

Number of hours worked by Arla in second week = 20

Number of hours worked by Kal in second week = 16

Total Money earned in second week = $580

So we can say that;

20x+16y=580   ⇒ equation 2

Now Multiplying equation 2 by 2 we get;

2(20x+16y)=580\times2

Applying Distributive property we get;

40x+32y =1160   ⇒ equation 3

Now Subtracting equation 3 from equation 1 we get;

(40x+40y)-(40x+32y)=1300-1160\\\\40x+40y-40x-32y=140\\\\8y=140

Now Dividing both side by 8 we get;

\frac{8y}{8}=\frac{140}{8}\\\\y= \$17.5

Now Substituting the value of y in equation 1 we get;

40x+40y=1300\\\\40x+40\times17.5 =1300\\\\40x+700=1300\\\\40x=1300-700\\\\40x=600\\\\x=\frac{600}{40}\\\\x=\$15

Hence The hourly wage of Arla is $15 and hourly wage of Kal is $17.5.

5 0
3 years ago
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