What is the measure of angle 3 in degrees?

Mathematics

1 answer:

blsea [12.9K]3 years ago

8 0

27 degrees (i think)

You might be interested in

Kelly is reading a 440-page book. During the past 5 days she has read 275 pages. At this rate, how many more days will it take h

adoni [48]

3 days, 275/5=55 pages/day. 440-275=165. 165/5=3

8 0

3 years ago

PLS HELP MEEEEEEEE PLS I NEED THIS ASAP

ki77a [65]

Answer:the first one is 16 and the second one I don’t know and it’s kinda hard to see

5 0

3 years ago

Read 2 more answers

Find the missing endpoint if S is the midpoint of RT R(-9,4) and S(2,-1) ; Find T

liraira [26]

Answer:

T is at (13,-6)

Step-by-step explanation:

x-coordinate of T: from -9 to 2, there's 11 units, so you add 11 to 2 to find the x-coordinate of T, which is 13.

y-coordinate of T: from 4 to -1 there's -5 units, so you subtract 5 from -1 to find the y-coordinate of T, which is -6.

4 0

3 years ago

(04.05 LC)

Komok [63]

correct answer is option d.

Step-by-step explanation:

Here, we have The following expression to check Which of the following is a polynomial with roots: −square root of 3 , square root of 3, and 2 :

a. x3 + 3x2 − 5x − 15

For $-\sqrt{3}$ , $x^{3} + 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3} + 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!

b. x3 + 2x2 − 3x − 6

For $-\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(-\sqrt{3}) ^{3} + 2(-\sqrt{3} )^{2} -3(-\sqrt{3} ) -6$ = 0 .

For $\sqrt{3}$ , $x^{3} + 2x^{2} -3x -6$ ⇒ $(\sqrt{3}) ^{3} + 2(\sqrt{3} )^{2} -3(\sqrt{3} ) -6$ = 0.

For 2 , $x^{3} + 2x^{2} -3x -6$ ⇒ $(2) ^{3} + 2(2)^{2} -3(2 ) -6$ $\neq 0$ . So, this isn't the one. We move on further!

c. x3 − 3x2 − 5x + 15

For $-\sqrt{3}$ , $x^{3}- 3x^{2} -5x -15$ ⇒ $(-\sqrt{3}) ^{3}- 3(-\sqrt{3} )^{2} -5(-\sqrt{3} ) -15$ $\neq 0$ . So, this isn't the one. We move on further!