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Marianna [84]
3 years ago
7

I’ll mark brainest, answer asap!!!

Mathematics
2 answers:
Alika [10]3 years ago
6 0

Answer:

It is 1

Step-by-step explanation:

Because it to the left 2 times and down 3 times which are both negative

seraphim [82]3 years ago
5 0

Answer:

The correct answer is 1

Step-by-step explanation:

I hope this helps with your question :)

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No link or bot answer right
Margaret [11]

Answer:

1/6^8

Step-by-step explanation:

the answer is the one right next to the submit answer

3 0
2 years ago
Formulate the situation as a system of two linear equations in two variables. Be sure to state clearly the meaning of your x- an
slega [8]

Answer:

1) There were 33 $4,000 investors and 27 $8,000 investors.

2) The solution in x = 4, y = 9.

3) There were 24 nickels and 56 dimes.

Step-by-step explanation:

1) A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing either $4,000 or $8,000. If the partnership raised $348,000, then how many investors contributed $4,000 and how many contributed $8,000?

I am going to say that:

x is the number of investors that contributed 4,000.

y is the number of investors that contributed 8,000.

Building the system:

There are 60 investors. So:

x + y = 60

In all, the partnership raised $348,000. So:

4000x + 8000y = 348000

I am going to simplify by 4000. So:

x + 2y = 87

Solving the system:

The elimination method is a method in which we can transform the system such that one variable can be canceled by addition. So:

1)x + y = 60

2)x + 2y = 87

I am going to multiply 1) by -1. So we have

1)-x - y = -60

2)x + 2y = 87

By addition, the x are going to cancel each other

-x + x - y + 2y = -60 + 87

y = 27

For x:

x + y = 60

x = 60-y = 60-27 = 33

There were 33 $4,000 investors and 27 $8,000 investors.

2) Solve the system by row-reducing the corresponding augmented matrix.

2x + y = 17

x + y = 13

This system has the following augmented matrix:

\left[\begin{array}{ccc}2&1&17\\1&1&13\end{array}\right]

To help the row reducing, i am going to swap the first with the second line:

L1  L2

So we have:

\left[\begin{array}{ccc}1&1&13\\2&1&17\end{array}\right]

Now, reducing the first column.

L2 = L2 - 2L1

So we have:

\left[\begin{array}{ccc}1&1&13\\0&-1&-9\end{array}\right]

Now we do:

L2 = -L2

And the matrix is:

\left[\begin{array}{ccc}1&1&13\\0&1&9\end{array}\right]

Now to reduce the second column, we do:

L1 = L1 - L2

\left[\begin{array}{ccc}1&0&4\\0&1&9\end{array}\right].

So the solution is:

x = 4, y = 9.

3) A jar contains 80 nickels and dimes worth $6.80. How many of each kind of coin are in the jar?

I am going to say that x is the number of nickels and y is the number of dimes.

Each nickel is worth 5 cents and each dime is worth 10 cents.

Building the system:

There are 80 coins in all:

x + y = 80

They are worth $6.80. So:

0.05x + 0.10y = 6.80

Solving the system:

1)x + y = 80

2)0.05x + 0.10y = 6.80

I am going to divide 1) by -10, so we can cancel y. So:

1)-0.10x - 0.10y = -8

2)0.05x + 0.10y = 6.80

Adding:

-0.10x + 0.05x - 0.10y + 0.10y = -8 + 6.80

-0.05x = -1.2 *(-100)

5x = 120

x = \frac{120}{5}

x = 24

Also

x + y = 80

y = 80-x = 80-24 = 56

There were 24 nickels and 56 dimes.

8 0
4 years ago
The illustration below is of the circle (x + 6)2 + (y + 7)2 = 4.<br><br><br> True<br><br> False
mafiozo [28]
True true true true true
3 0
3 years ago
Read 2 more answers
6E and 7 with full explanation
ELEN [110]

Answer:

See below ~

Step-by-step explanation:

Question 6(e) :

⇒ x² ≤ 16

<em>Take square root on each side :</em>

⇒ √x² ≤ √16

⇒ x ≤ 4 and x ≥ -4

⇒ -4 ≤ x ≤ 4

7 0
2 years ago
Read 2 more answers
PLEASE GUYS HELP QUICK. PLEASE DO EVERYTHING IT ASKS YOU TO DO show work and ect , I'M OFFERING 15PTS ( More than its worth) And
Anvisha [2.4K]
A. W = L - 10

b. P = 2(L + L - 10)
    P = 2(2L - 10)
    P = 4L - 20

c. solve 
     P = 4L - 20
 244 = 4L - 20
244 + 20 = 4L
264 = 4L
264 / 4 = L
66 = L or L = 66
Length of the rectangle = 66  mm

d. 
W = L - 10
W = 66 - 10
W = 56
Width of rectangle  = 56 mm

5 0
3 years ago
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